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pav-90 [236]
3 years ago
7

One sign lights up every 10 seconds. One sign lights up every 12 seconds. If they have just lit up at the same time, how many se

conds will it take for the signs to light up at the same time again?
Mathematics
1 answer:
andrew11 [14]3 years ago
7 0

Answer:

It will take 60 seconds for the signs to light up at the same time again.

Step-by-step explanation:

Given:

One sign lights up every 10 seconds

One sign lights up every 12 seconds

They have just lit up at the same time.

To find in how many seconds will it take for the signs to light up at the same time again.

Solution:

In order to find the time in seconds will it take for the signs to light up at the same time again, we need to find the least common multiple of the the times for which the given signs light up.

The numbers are 10 and 12.

To find the LCM, we will list the multiples of each and check the least common multiple.

The multiples of 10 and 12 are :

10\rightarrow 10,20,30,40,50,60,70

12\rightarrow 12,24,36,48,60

thus, we can see that 60 is the least common multiple.

Thus, the signs will light up at the same time time after every 60 seconds.

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To rewrite your question, you are looking for the smallest    that fulfills the inequality:

∑=1>250

First, we must find the sequence    in explicit form. We can think of it as a line we are trying to get the slope-intercept form of. We have the points (1, 3) and (2, 8). Therefore, the slope is  8−32−1=51=5 . Now we just need the y-intercept. We can find it through substitution:

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In order to solve for   , we can plug in one of the points that we were already given. I will choose the point (1, 3). Note that this point just means that when  =1 ,  =3 .

3=5(1)+

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=−2

Now for the original question.

∑=1(5−2)>250

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2+15>100

2+15+1100>100+1100

(+110)2>100+1100

(+110)2>10001100

+110>±10001100‾‾‾‾‾‾‾√

+110>±11010001‾‾‾‾‾‾√

>−110±11010001‾‾‾‾‾‾√

Since we are looking for the smallest value, we will subtract for the plus or minus sign.

>−110−11010001‾‾‾‾‾‾√≈−10

Since that is negative, we will have to add instead.

>−110+11010001‾‾‾‾‾‾√≈9.9

Therefore, the smallest integer    that makes sense and satisfies the inequality is 10.

So, the first 10 numbers must be added.

Honestly, it would have been quicker just to brute-force this.

Step-by-step explanation:

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Answer:

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