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olga nikolaevna [1]
3 years ago
13

Your class is in groups, working on a combinatorics worksheet. One of the questions asks how many possible ways 5 books out of a

box of 12 can be placed on a shelf. Your classmate suggests you calculate 12C5, which is 792. What would you say to explain how this suggestion is flawed, and how would you help correct them
Mathematics
1 answer:
Sergeu [11.5K]3 years ago
5 0

Answer: 95040

Step-by-step explanation:

It is important to note that selection and arrangement are two different things in permutation and combination study. In the scenario above, we have 12 books, out of which 5 is to be arranged on a shelf. The answer prescribed by 12C5 which gives 792, only solves the selection process of choosing 5 books from a total of 12. Every 5 books picked will also have to be arranged on the shelf which is solved as n!(number of ways of arranging n different objects)

Hence, to arrange 5 books from a total of 12 books on a book shelf is

nCr * r!

12C5 * 5!

792 * 120

= 95040

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In the data set below, which of these points is most likely and outlier?
shusha [124]
<h2>Answer:</h2>

Option: D is the correct answer.

                 D.  (2,54)

<h2>Step-by-step explanation:</h2>

We know that an outlier of a data set is the value that stands out of the rest of the data point i.e. either it is a too high value or a too low value as compared to other data points.

Here  we are given a set of data points as:

         (2,54)

          (4,7)

         (6, 9)

         (8,12)

         (10,15)

Hence, we see that the output values i.e. 7 in (4,7) ; 9 in (6,9) ; 12 in (8,12) and 15 in (10,15) are closely related.

Hence, the data point that is an outlier is:

                  (2,54)

(As 54 is a much high value as compared to other)

5 0
3 years ago
In the field of quality​ control, the science of statistics is often used to determine if a process is​ "out of​ control." Suppo
Usimov [2.4K]

Answer:

a) P=0.0225

b) P=0.057375

Step-by-step explanation:

From exercise we have that  15​% of items produced are defective, we conclude that  probabiity:

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P=0.15

a)  We calculate the probabiity  that two items are​ defective:

P= 0.15 · 0.15

P=0.0225

b)  We calculate the probabiity  that  two  of  three items are​ defective:

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P=\frac{3!}{2!(3-2)!} · 0.019125

P=3 · 0.019125

P=0.057375

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MaRussiya [10]
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3 years ago
What is 99,999 rounded to the nearest thousands
konstantin123 [22]
100,000

is the answer 
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3 years ago
Read 2 more answers
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