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Minchanka [31]
3 years ago
11

What is the value of x and the length of segment DE?

Mathematics
2 answers:
Oduvanchick [21]3 years ago
6 0

Answer:

X= 6.6

Length of de = 16.2

Step-by-step explanation:

kaheart [24]3 years ago
3 0

My reactions to this:

???

My notes to you:

This is confusing... (At least for me it is...)

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Father's age is five times than the son's age. If the sum
sweet [91]

Answer:

The son is 10, and the father is 50.

Step-by-step explanation:

10 times 5 would be 50, and 50+10 is 60.

4 0
3 years ago
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40 POINTS!!!!!!!! NEED HELP
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Where is the grid are u gonna take a pic?
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Determine if each set of ordered pairs represents a function
Nostrana [21]
Where is the picture?
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2 years ago
What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu
inn [45]

Answer:

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Step-by-step explanation:

The given expression is

\frac{2x+5}{x^{2} -3x} -\frac{3x+5}{x^{3} -9x} -\frac{x+1}{x^{2}-9}

First, we need to factor each denominator

\frac{2x+5}{x(x-3)} -\frac{3x+5}{x(x+3)(x-3)} -\frac{x+1}{(x-3)(x+3)}

So, the least common factor (LCF) is x(x-3)(x+3), because they are the factors that repeats.

Now, we diviide the LCF by each denominator, to then multiply it by each numerator.

\frac{(x+3)(2x+5)-3x-5-x(x+1)}{x(x-3)(x+3)} =\frac{2x^{2}+5x+6x+15-3x-5-x^{2}-x }{x(x-3)(x+3)}\\\frac{x^{2}+7x+10}{x(x-3)(x+3)}

Then, we factor the numerator, to do so, we need to find two numbers which product is 10 and which sum is 7.

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Therefore, the expression is equivalent to

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

8 0
2 years ago
Read 2 more answers
Consider the following system of equations. StartLayout Enlarged left-brace 1st row negative 10 x squared minus 10 y squared = n
ziro4ka [17]

These 2 equations has no solution and the equations are independent of each other.

<u>Step-by-step explanation:</u>

-10x² -10y² = -300 ----a

5x² + 5y² = 150 ---- b

While trying to solve this,

We can multiply the eq. b by 2 so we will get eq. c and then add to eq. a we will get 0 as the solution.

10x² + 10y² = 300 ----c

-10x² -10y² = -300 ---a

Everything cutoff, we will get 0, and there is no solution to these equations.

4 0
3 years ago
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