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Alexxandr [17]
3 years ago
9

A farmer wants to fence an area of 24 million square feet in a rectangular field and then divide it in half with a fence paralle

l to one of the sides of the rectangle. What should the lengths of the sides of the rectangular field be so as to minimize the cost of the fence?
smaller value? and larger value?
Mathematics
1 answer:
Maurinko [17]3 years ago
5 0
Use half the fencing in each direction: 3 segments in one direction, 2 in the other. 

<span>W * L = 24 million </span>
<span>3 W = 2 L </span>

<span>W * 3 W / 2 = 24 million </span>
<span>W^2 = 16 million </span>
<span>W = 4000 </span>
<span>L = 6000 </span>

<span>This shortcut (3 W = 2 L) </span>
<span>is derived from total fencing = 3W + 2L </span>
<span>and W*L = 24 million </span>
<span>total fencing = 3W + 2 * 24 million / W </span>
<span>and taking the derivative, setting to 0, and solving for W</span>
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When purchasing bulk orders of​ batteries, a toy manufacturer uses this acceptance sampling​ plan: Randomly select and test 56 b
nydimaria [60]

Answer:

98.1% chance of being accepted

Step-by-step explanation:

Given:

sample size,n=56

acceptance condition= at most 2 batteries do not meet specifications

shipment size=7000

battery percentage in shipment that do not meet specification= 1%

Applying binomial distribution

<h3>P(x)=∑ᵇₐ=₀ (n!/a!(n-a)!)p^a (1-p)^(n-a)</h3>

In this formula, a is the acceptable number of defectives;

 n is the sample size; 

p is the fraction of defectives in the population.  

Now putting the value

a= 2

n=56

p=0.01

\frac{56!}{0!\left(56-0\right)!}\left(0.01\right)^0\:\left(1-0.01\right)^{\left(56-0\right)} + \frac{56!}{1!\left(56-1\right)!}\left(0.01\right)^1\:\left(1-0.01\right)^{\left(56-1\right)} +\:\frac{56!}{2!\left(56-2\right)!}\left(0.01\right)^2\:\left(1-0.01\right)^{\left(56-2\right)}

=0.56960+0.32219+0.08949

After summation, we get 0.981 i.e. a 98.1% chance of being accepted.  As this is such a high chance, we can expect many of the shipments like this to be accepted!

7 0
2 years ago
A rental car company charges $53.75 per day to rent a car and $0.12 for every mile driven. Jaya wants to rent a car, knowing tha
Aliun [14]

Answer:

Jaya can afford to rent a car 4 days while staying within her budget.

Step-by-step explanation:

The inequality would have to indicate that the cost of renting a car has to be less than or equal to $230. The cost to rent a car is equal to the cost per day for the number of days plus the price per mile for the number of miles, which is:

53.75x+0.12y≤230, where:

x is the number of days the car is rented

y is the number of miles driven

As the statement says that she plans to drive 125 miles, you can replace "y" with this value and solve for x:

53.75x+0.12(125)≤230

53.75x+15≤230

53.75x≤230-15

53.75x≤215

x≤215/53.75

x≤4

According to this, the answer is that Jaya can afford to rent a car 4 days while staying within her budget.

5 0
3 years ago
A line passes through the point (-4, -2) and has a slope of -5/2. Write an equation in slope- intercept form for this line.
kirill115 [55]

Answer:

<h2>           y = -⁵/₂x - 12 </h2>

Step-by-step explanation:

The point-slope form of the equation is y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through and m is the slope:

m = -⁵/₂

(-4, -2)    ⇒   x₀ = -4,  y₀ = -2

The point-slope form of the equation:

y + 2 = -⁵/₂(x + 4)

So:

y + 2 = -⁵/₂x - 10         {subtract 2 from both sides}

y = -⁵/₂x - 12             ←  the slope-intercept form of the equation

5 0
2 years ago
One container is filled with a mixture that is 30%acid a second container is filled with a mixture that is 50%acid the second co
julsineya [31]

Answer:

The amount of acid in third container is =42%

Step-by-step explanation:

Given , one container is filled with a mixture that is 30% acid a second container filled with a mixture that is 50% acid and the second container 50% larger than the first .

Let, the volume of first container is = x

Then , the volume of second container = (x+ x of 50%)

                                                                 = x + 0.5 x

                                                                 = 1.5 x

Therefore the amount of acid in first container =x \times \frac{30}{100} = 0.3 x

The amount of acid in second container =1.5x \times \frac{50}{100}  = 0.75x

Total amount of acid= 0.3x + 0.75x = 1.05 x

Total amount  of solution = x+1.5x = 2.5x

The amount of acid in third container is = \frac{1.05x}{2.5x} \times 100% %

                                                                     = 42%

4 0
3 years ago
This is old work i forget how to do it
dexar [7]

Answer:

1.101, 1.001, and 0.113

Step-by-step explanation:

the first on is the highest

plz leave a like and brainlest!! i need 10 to ask a quistion!!!

5 0
2 years ago
Read 2 more answers
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