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3 years ago

Hey somebody please help me with this

Mathematics

1 answer:

kvv77 [185]3 years ago

4 0

Try the first option A

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(7^4)(7^2) = A) 7^6 B) 7^8 C) 14^6 D) 14^8

jonny [76]

Answer:

Step-by-step explanation:

using the rule of exponents

• $a^{m}$ × $a^{n}$ ⇔ $a^{(m+n)}$ , hence

$7^{4}$ × 7² = $7^{(4+2)}$ = $7^{6}$

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3 years ago

Brianna wants to save the $250 she earned by babysitting over the summer. She's trying to decide which

Nookie1986 [14]

Answer:

Total cost = Cost per month × 12 months per year × Number of years

= $21 × 12 × 8

= $2,016

Step-by-step explanation:

8 0

2 years ago

In need of help PLEASE!!!!

ozzi

Answer:

a bc I think it's right idk really

Step-by-step explanation:

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2 years ago

Find the term to term rules for the following sequences:<br> 2, 6, 18, 54, 162

ki77a [65]

The term rules for the following sequences is that you multiply each number by 3! Hope this helps and please mark brainliest :)

6 0

3 years ago

Read 2 more answers

Intravenous fluid bags are filled by an automated filling machine. Assume that the fill volumes of the bags are independent, nor

kenny6666 [7]

Answer:

a) 0.0167

b) 0

c) 5.948

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.16 ounces

Standard Deviation, σ = 0.08 ounces

We are given that the distribution of fill volumes of bags is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) Standard deviation of 23 bags

$\displaystyle\frac{S.D}{\sqrt{23}} = \frac{0.08}{\sqrt{23}} = 0.0167$

b) P( fill volume of 23 bags is below 5.95 ounces)

P(x < 5.95)

$P( x < 5.96) = P( z < \displaystyle\frac{5.95 - 6.16}{0.0167}) = P(z < -12.57)$

$= 1 - P(z < 12.57)$

Calculation the value from standard normal z table, we have,

$P(x < 5.95) = 1 - 1 = 0$

c) P( fill volume of 23 bags is below 6 ounces) = 0.001

P(x < 6) = 0.001

$P( x < 6) = P( z < \displaystyle\frac{6 - \mu}{0.0167})$

Calculation the value from standard normal z table, we have,

$P( z \leq -3.09) = 0.001$

$\displaystyle\frac{6 - \mu}{0.0167} = -3.09\\\\\mu = 6 + (0.0167\times -3.09) = 5.948$

If the mean will be 5.948 then the probability that the average of 23 bags is below 6.1 ounces is 0.001.

7 0

3 years ago