Question

Given a link with a maximum transmission rate of 28.1 Mbps. Only two computers, X and Y, wish to transmit starting at time t = 0 seconds. Computer X sends fileX (10 MiB) and computer Y sends fileY (14 KiB), both starting at time t = 0.
Statistical multiplexing is used, with details as follows
Packet Payload Size = 1000 Bytes
Packet Header Size = 24 Bytes (overhead)
Ignore Processing and Queueing delays
Assume partial packets (packets consisting of less than 1000 Bytes of data) are padded so that they are the same size as full packets.
Assume continuous alternating-packet transmission.
Computer X gets the transmission medium first.
At what time (t = ?) would FileX finish transmitting?

Give answer in seconds, without units, and round to two decimal places (e.g. for an answer of 12.4567 seconds you would enter "12.46" without the quotes)

Answer 1

Answer:

0.36

Explanation:

Each Packet Size = 1024 bytes (1000 bytes + 24 bytes)

X gets the transmission first.

Number of packets X has to send = 10,000,000 / 1,000 = 10,000 packets.

Number of packets Y has to send = 14,000 / 1,000 = 14 packets.

Time for one packet to transmit:

28,100,000 bytes in 1 sec

1,024 bytes in = (1/28,100,000) * 1,024 = 0.00003644 secs.

Time taken for X to send = 10,000 * 0.00003644 = 0.3644 secs

Time taken for Y to send = 14 * 0.00003644 = 0.00051016 secs

Time at which File x would finish transmitting = 0.3644 + 0.00051016 = 0.36

Hope this helps!