The python code which can be used to read dates from input, one date per line and each date's format must be as follows: March 1, 1990, is:
<h3>Python code</h3>
import datetime
inputs = []
result = []
#read the inputs
date = input()
inputs.append(date)
while not date == "-1":
date = input()
inputs.append(date)
#check if the input is in the correct format and convert it.
for date_text in inputs:
try:
date_text = datetime.datetime.strptime(date_text,"%d %B, %Y")
result.append(date_text.strftime("%d/%m/%Y"))
except ValueError:
pass
print(*result, sep = "\n")
The above code would parse the string and extract the date. The split() method was used to break the input into tokens.
Read more about python programming here:
brainly.com/question/27666303
#SPJ1
Answer:
It goes like:
public class Program
{
public static void main(String[] args)
{
int j=18;
int sum=0;
for (int i =1; i<7; i++)
{
sum=sum+(i*(j-2));
j=j-2;
}
System.out.println(sum);
}
}
Explanation:
<u>Variables used: </u>
j : controls the first number in product and decreases by 2 each time the loop runs.
sum: saves the values of addition as the loop runs.
Answer:
blank 4
Explanation:
I just did this assignment got 100
The range of cells in column A and rows 10 through 20
