Here are the multiple choices below:
A. Sort sugar in descending order, and filter Calories by under 100 calories.
B. Sort sugar in ascending order, and filter Calories by over 100 calories.
C. Filter Calories by over 100 calories, and sort Sugar in descending order.
D. Filter Calories by over 100 calories, and sort Sugar in ascending order.
Sorting and Filtering in Excel or Access are two tools that let you organize and view your data. Sorting your data puts it in order and filtering lets you hide unimportant data. And in this case, it is no different. If you want to show foods with more than 100 calories, you should filter calories by over 100 and sort sugar in highest to the lowest (descending order).
Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.
public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}
So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.
A quick explanation:
We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.
The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.
Answer:
The answers are "Option a, Option b, Option d, and Option c".
Explanation:
- The Traceroute utilizes the "Internet Control Message Protocol" for transmit and receive echo-request and echo-reply messages. This is most often used in the echo packets of specified interval to live (TTL) quantities.
- The Transport layer will be the next but is usually directly linked with the same name layer in the OSI model. Functions involve message fragmentation, acknowledgment, traffic management, session parallelization, error detection, as well as message rearranging.
- Leaders generally fully involve one or even more workers in design buildings.
- 67 was its UDP port number which is used as the port number of a database. So although UDP port number 68 is being used by the client.
I’m not 100% sure about this but I think it is A
