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Nonamiya [84]
4 years ago
5

find the equation of a straight line passing through the points (3,2)and (-3,6)giving the answer in the form x/a+y/b ,where a an

d b are constants
Mathematics
1 answer:
klio [65]4 years ago
7 0
Slope of line = \frac{6-2}{-3-3}= \frac{4}{-6}  =- \frac{2}{3}

the equation : (y-2)= \frac{-2}{3}(x-3)

3y - 6 = -2x + 6,     2x+3y =12  (you can divide by 12 to get the equation straight away)

to get the intercept of both the x-axis and y-axis:

the intercept of x-axis (y=0) , 2x=12 , x = 6

the intercept of y-axis (x=0) , 3y=12 , y = 4

the equation is : \frac{x}{6} + \frac{y}{4} =1
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New equation (the ones in bold are the changes): 2/3(6c+4)+(-8c)+(5)
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Step-by-step explanation:

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Step-by-step explanation:

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