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arsen [322]
3 years ago
5

Let y = f(x be the solution to the differential equation dy/dx = x y with the intial condition f(1=2. what is the approximation

for f(2 if euler's method is used, starting at x=1, with a step size of 0.5
Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
6 0
Denote the ODE by

\dfrac{\mathrm dy}{\mathrm dx}=g(x,y)=xy

For this equation, you'll be using the recurrence relation

\begin{cases}y_{n+1}=y_n+hg(x_n,y_n)\\x_{n+1}=x_n+h\\x_0=1\\y_0=2\\h=0.5\end{cases}

You have

f(1.5)\approx y_1=y_0+0.5x_0y_0=2+0.5(1)(2)=3
f(2)\approx y_2=y_1+0.5x_1y_1=3+0.5(1.5)(3)=5.25
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A gym membership charges $100 for a start up fee and $40 a month for
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The equation that represents the cost of membership is  $100 + $40c

The cost of 1 year membership is $580.

The number of months you have paid for is 9 months.

<h3>What is the equation that represents the cost of the gym membership?</h3>

The cost of gym membership is the sum of the fixed cost and the variable cost. The fixed cost is the start-up fee while the variable cost is the cost per month.

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Eric earned 60 points on his last test. If there were 75 possible points, what was his percent grade?
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Please I Really Need Help.The coordinate plane below represents a city. Points A through F are schools in the city.
almond37 [142]

Answer:

Part A) The system of inequalities is

x\geq2  and  y\geq2

Part B) In the procedure

Part C) The schools that Natalie is allowed to attend are A,B and D

Step-by-step explanation:

Part A: Using the graph above, create a system of inequalities that only contain points C and F in the overlapping shaded regions

we have

Points C(2,2), F(3,4)

The system of inequalities could be

x\geq2 -----> inequality A

The solution of the inequality A is the shaded area at the right of the solid line x=2

y\geq2 -----> inequality B

The solution of the inequality B is the shaded area above of the solid line y=2

see the attached figure N 1

Part B: Explain how to verify that the points C and F are solutions to the system of inequalities created in Part A

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities

<em>Verify point C</em>

C(2,2)    

<em>Inequality A</em>

x\geq2 -----> 2\geq2 ----> is true

<em>Inequality B</em>

y\geq2 ------> 2\geq2 ----> is true

therefore

Point C is a solution of the system of inequalities

<em>Verify point D</em>

F(3,4)    

<em>Inequality A</em>

x\geq2 -----> 3\geq2 ----> is true

<em>Inequality B</em>

y\geq2 ------> 4\geq2 ----> is true

therefore

Point D is a solution of the system of inequalities

Part C: Natalie can only attend a school in her designated zone. Natalie's zone is defined by y < −2x + 2. Explain how you can identify the schools that Natalie is allowed to attend.

we have

y < -2x+2

The solution of the inequality is the shaded area below the dotted line y=-2x+2

The y-intercept of the dotted line is the point (0,2)

The x-intercept of the dotted line is the point (1,0)

To graph the inequality, plot the intercepts and shade the area below the dotted line

see the attached figure N 2

therefore

The schools that Natalie is allowed to attend are A,B and D

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