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arsen [322]
3 years ago
5

Let y = f(x be the solution to the differential equation dy/dx = x y with the intial condition f(1=2. what is the approximation

for f(2 if euler's method is used, starting at x=1, with a step size of 0.5
Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
6 0
Denote the ODE by

\dfrac{\mathrm dy}{\mathrm dx}=g(x,y)=xy

For this equation, you'll be using the recurrence relation

\begin{cases}y_{n+1}=y_n+hg(x_n,y_n)\\x_{n+1}=x_n+h\\x_0=1\\y_0=2\\h=0.5\end{cases}

You have

f(1.5)\approx y_1=y_0+0.5x_0y_0=2+0.5(1)(2)=3
f(2)\approx y_2=y_1+0.5x_1y_1=3+0.5(1.5)(3)=5.25
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3 years ago
Sophia had 64¢ until she spent 1 quarter. How much money does Sophia have now?
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Answer:

Sophia now has 39 cents.

Step-by-step explanation:

One quarter = 25 cents

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Yo! Solving linear equations with integers! These are just some practice exercises I need help with! So they should probably be
drek231 [11]

Answer:

Step-by-step explanation:

<h3>Solving linear equation with one variable:</h3>

   1) -4 + 3x = 4x - 8

        Add 4 to both sides

      -4 + 3x + 4 = 4x - 8 +  4

               3x     = 4x - 4

Subtract 4x from both sides,

        3x - 4x = -4x + 4x - 4

              -x   = -4

                \sf \boxed{\bf x = 4}

2) -5x - 8 = 2

Add 8 to both sides

 -5x - 8 + 8 = 2 + 8

            -5x  = 10

Divide both sides by (-5)

            \sf \dfrac{-5}{-5}x =\dfrac{10}{-5}

                 \sf \boxed{\bf x = -2}

3) 12r - 14 = 5(2-r)

    12r - 14 = 5*2 - 5*r

     12r - 14 = 10 - 5r

Add 14 to both sides

 12r - 14 + 14 = 10 - 5r + 14

             12r  = 24 - 5r

Add 5r to both sides

        12r + 5r = 24

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Divide both sides by 17

                 r = 24/17

4) 3x - 8 = -(17 + 2x)

  3x - 8 = -17 - 2x

Add 8 to both sides

3x - 8 + 8 = -17 - 2x + 8

           3x = -9 - 2x

Add 2x to both sides

      3x + 2x = -9

            5x  = -9

Divide both sides by 5

              \sf \dfrac{5}{5}x=\dfrac{-9}{5}\\\\\boxed{x = \dfrac{-9}{5}}

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