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pishuonlain [190]
3 years ago
7

A compound that contains both potassium and oxygen formed when potassium metal was burned in oxygen gas. the mass of the compoun

d was 7.11 grams. The mass of the potassium metal was 3.91 grams. What mass of oxygen was involved in this reaction? Justify your answer.
Chemistry
2 answers:
Artemon [7]3 years ago
4 0
Answer:
             3.2 g of O₂

Solution:
             This reaction is for the formation of Potassium Superoxide, The reaction is as follow,

                                           K  +  O₂     →     KO₂

First let us confirm that either the given amount of Potassium produces the given amount of Potassium oxide or not,
So,
As,
                39.098 g (1 mole) K produced  =  71.098 g of K₂O
So,
                          3.91 g of K will produce  =  X g of K₂O

Solving for X,
                      X  =  (3.91 g × 71.098 g) ÷ 39.098

                      X  =  7.11 g of K₂O

Hence, it is confirmed that we have selected the right equation,
So,
As,
                     39.098 g of K required  =  32 g of O₂
So,
                     3.91 g of K will require  =  X g of O₂

Solving for X,
                     X  =  (3.91 g × 32 g) ÷ 39.098 g

                     X  =  3.2 g of O₂
Sladkaya [172]3 years ago
4 0
The mass of oxygen  that was involved  in the reaction is calculated as below

 mass of the oxygen =mass of the  compound- mass  of the  potassium

that is  7.11 grams -3.91 grams= 3.2  grams  of oxygen  is involved

This is because the mass of the compound composes the mass of potassium + mass of the oxygen
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