<span>Answer:
Ground state of Hydrogen = -13.6 eV Energy of photon emission: E = hf = hc/λ = 6.6256E-34 (3E8)/680E-9 E = 0.0292E-17 J(1 eV/1.6E-19 J) = 1.825 eV E(photon) = 1.825 eV Bandgap energy: ΔE = E – Eo = 1.825 – (-13.6) = 15.425 eV</span>
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Answer:
<em>Recall the following terms which is,</em>
<em> KHP is Potassium hydrogen phthalate</em>
<em>NaOH is Sodium Hydroxide </em>
<em>NaKP is molar mass</em>
<em>H20 is water</em>
Explanation:
<em>KHP + NaOH = NaKP + H2O
</em>
<em>moles of KHP = 0.3480g / 204.22 g·mol−1 = .001704
</em>
<em>these will react with the same number of moles of NaOH according to the equation </em>
<em>these are in 0.03207 L of solution </em>
<em> The molarity of the NaOH solution = 0.001704 mol / 0.03207 L = 0.0531 M
</em>
<em>the water takes no part in the reaction and the quantity can be ignored
</em>
<em />
Answer: The rate constant is
Explanation ;
Expression for rate law for first order kinetics is given by:

where,
k = rate constant = ?
t = age of sample = 4.26 min
a = initial amount of the reactant = 2.56 mg
a - x = amount left after decay process = 2.50 mg
Now put all the given values in above equation to calculate the rate constant ,we get



Thus rate constant is [tex]0.334s^{-1}