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pishuonlain [190]
3 years ago
7

A compound that contains both potassium and oxygen formed when potassium metal was burned in oxygen gas. the mass of the compoun

d was 7.11 grams. The mass of the potassium metal was 3.91 grams. What mass of oxygen was involved in this reaction? Justify your answer.
Chemistry
2 answers:
Artemon [7]3 years ago
4 0
Answer:
             3.2 g of O₂

Solution:
             This reaction is for the formation of Potassium Superoxide, The reaction is as follow,

                                           K  +  O₂     →     KO₂

First let us confirm that either the given amount of Potassium produces the given amount of Potassium oxide or not,
So,
As,
                39.098 g (1 mole) K produced  =  71.098 g of K₂O
So,
                          3.91 g of K will produce  =  X g of K₂O

Solving for X,
                      X  =  (3.91 g × 71.098 g) ÷ 39.098

                      X  =  7.11 g of K₂O

Hence, it is confirmed that we have selected the right equation,
So,
As,
                     39.098 g of K required  =  32 g of O₂
So,
                     3.91 g of K will require  =  X g of O₂

Solving for X,
                     X  =  (3.91 g × 32 g) ÷ 39.098 g

                     X  =  3.2 g of O₂
Sladkaya [172]3 years ago
4 0
The mass of oxygen  that was involved  in the reaction is calculated as below

 mass of the oxygen =mass of the  compound- mass  of the  potassium

that is  7.11 grams -3.91 grams= 3.2  grams  of oxygen  is involved

This is because the mass of the compound composes the mass of potassium + mass of the oxygen
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Answer:

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Hence, the ratio is 1 C atom / 1 Na₂CO₃ unit formula.

This is, there is 1 atom of carbon per each unit formula of sodium carbonate.

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Since, the ratio is 1: 1, the number of moles of sodium carbonate is the same number of moles of carbon atoms.

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Determine the number of protons, electrons, neutrons, valence electrons and valency in Oxygen atom (O) and Oxide ion (O2-). Comp
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Answer:

<em />

<em>                    Atom (O)           Ion (O²⁻)</em>

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<em>Electrons          8                      10</em>

<em>Neutrons          8                       8   </em>      ← only for the oxygen-16 isotope.

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Explanation:

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Protons have relative positive charge equal to +1 and electrons have relative negative charge -1: same magnitude opposite sign.

Thus, the neutral oxygen, O, has also 8 electrons and 8 protons.

As per the number neutrons it depends on the specific isotope.

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Oxide ion O²⁻ is the oxygen ion with -2 charge, meaning that it has 2 more electrons than protons. Then, it has 8 protons and 10 electrons, again the number of neutrons depend of the specific isotope.

The stability of an atoms or ion refers to its trend to remain in the same state or react to form another species. The ions O²⁻ are less stable than the neutral atoms O, because the negative charge will be attracted to any positive ion so ti will react faster than the neutral oxygen atom (O).

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