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3 years ago

13

A mystery number between 0 and 1 ends at the thousands place, is 0.68 when rounded to the hundredths place. What is the smallest

the number can be?

1 answer:

Nina [5.8K]3 years ago

3 0

0.680 :3
Love ya!!
~~0.68~~

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Given the conditional statement, match the following.

Step2247 [10]

Hypothesis (p): A polygon is a square

Conclusion: (q): It is a rectangle

Inverse: q → p <em>If a polygon is a rectangle, then it is a square</em>

Converse: ~p → ~q <em>If a polygon is not a square, then it is not a rectangle.</em>

Contrapositive: ~q → ~p <em>If a polygon is not a rectangle, then it is not a square</em>

Your answers are correct

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3 years ago

A small rocket is fired from a launchpad 15 m above the ground with an initial velocity left angle 400,450,600 right angle m/s.

vivado [14]

Answer:

a)

v=<400, 450+3t, 600-9.81t> m/s

r=<400t, 450t+3 $t^{2}$ /2, 15+600t-9.81 $t^{2}$ /2> m/s

b) attach file

c) t=122.324s

d) z=18369.9854 m

Step-by-step explanation:

a)

The equation for velocity of each component is v= $v_{0}$ +at, in this case the x-axis component has acceleration 0 $\frac{m}{s^{2} }$ , the y-axis component has acceleration 3 $\frac{m}{s^{2} }$ and the z-axis component has -g $\frac{m}{s^{2} }$ , where g=9.81 $\frac{m}{s^{2} }$ .

The equation for position of each component is x= $x_{0}$ + $v_{0}$ t+a $t^{2}$ /2,

with < $x_{0}$ , $y_{0}$ , $z_{0}$ >=<0,0,15>.

c) This time is t when z=0, with positive sign.

d)Solving the equation $V_f^{2}$ = $V_o^2$ + 2*a*(z- $z_{0}$ ) for z, with $V_f$ =0.

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3 years ago

What is 80, 023 written in scientific notation? send help bbys.

Naddika [18.5K]

Answer:

8.0023 x 10^4

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3 years ago

TO TRANSMIT INFORMATION ON THE INTERNET, LARGE FILES ARE BROKEN INTO PACKETS OF SMALLER SIZES. EACH PACKET HAS 1,500 BYTES OF IN

borishaifa [10]

Answer:

<u>A. It would be needed 20 packets to transmit 30,000 bytes of information.</u>

<u>B. 45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.</u>

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Size of each packet of information = 1,500 bytes

Number of packets = P

Number of bytes of information = B

2. Let's answer the questions:

A. How many packets would be needed to transmit 30,000 bytes of information?

P = 30,000 ÷ 1,500

P = 20

<u>It would be needed 20 packets to transmit 30,000 bytes of information</u>

<u>B. </u>How much information could be transmitted in 30,000 packets?

B = 30,000 * 1,500

B = 45'000,000

<u>45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.</u>

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3 years ago

In a random sample of 30 people who rode a roller coaster one day, the mean wait time is 46.7 minutes with a standard deviation

Rainbow [258]

Answer: C. $(29,\ 37.8)$

Step-by-step explanation:

The confidence interval for difference of two population mean is given by :-

$\overline{x}_1-\overline{x}_2\pm z_{\alpha/2}\sqrt{\dfrac{s_1^2}{n_1}+\dfrac{s_2^2}{n_2}}$

Given : Level of significance : $1-\alpha:0.99$

Then , significance level : $\alpha: 1-0.99=0.01$

Critical value : $z_{\alpha/2}=z_{0.005}=2.576$

$n_1=30\ ;\ n_2=50\\\\\overline{x}_1=46.7\ ;\ \overline{x}_2=13.3\\\\s_1=9.2\ ;\ s_2=1.9$

$46.7-13.3\pm(2.576)\sqrt{\dfrac{9.2^2}{30}+\dfrac{1.9^2}{50}}\approx33.4\pm4.38=(29.02\ ,37.78)\approx(29,\ 37.8)$

Hence, a 99% confidence interval for the difference between the mean wait times of everyone who rode both rides $(29,\ 37.8)$

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4 years ago