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Rzqust [24]
3 years ago
11

12. What percent of 60 is 12? Show your work.

Mathematics
2 answers:
igomit [66]3 years ago
7 0
It is 7.2 because if you times .600 X 12 you get 7.2
lora16 [44]3 years ago
6 0
12 is 20% of 60 because 12/60 = 0.2.
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There are 28 days in 4 weeks. What fact family would you use to find the number of days in 1week
rusak2 [61]
Divide 28 by 4 so that number is 1 week because 28/4 is 7 and there is 7 days in a week
6 0
3 years ago
A(n) _____ is the intersection of a solid and a plane
8_murik_8 [283]
A cross-section <span>is the intersection of a solid and a plane.  </span>
7 0
3 years ago
Solve -1.2x+2.5=0.8x+6.5<br>x=2<br>O<br>x=-4 0​
Bond [772]

Answer:

x = - 2

Step-by-step explanation:

Given

- 1.2x + 2.5 = 0.8x + 6.5 ( subtract 0.8x from both sides )

- 2x + 2.5 = 6.5 ( subtract 2.5 from both sides )

- 2x = 4 ( divide both sides by - 2 )

x = - 2

4 0
3 years ago
How do u regroup when u find the sum of 64+43
Anarel [89]
What we are going to do is use the DISTRIBUTIVE PROPERTY. This distributive the numbers, to make it easier to solve.

So we will break 64 up.

64 = 60 + 4

43 = 40 + 3

60 + 40 = 100

4 + 3 = 7

100 + 7 = 107

So, 64 + 43 = 107.

Hope I helped ya!!!!!!!

6 0
3 years ago
Read 2 more answers
The numbers​ 1, 2,​ 3, 4, and 5 are written on slips of​ paper, and 2 slips are drawn at random one at a time without replacemen
mamaluj [8]
<h2>Answer:</h2>

(a)

The probability is :  1/2

(b)

The probability is :  1/2

<h2>Step-by-step explanation:</h2>

The numbers​ 1, 2,​ 3, 4, and 5 are written on slips of​ paper, and 2 slips are drawn at random one at a time without replacement.

The total combinations that are possible are:

(1,2)   (1,3)    (1,4)    (1,5)

(2,1)   (2,3)   (2,4)   (2,5)

(3,1)   (3,2)   (3,4)   (3,5)

(4,1)   (4,2)   (4,3)   (4,5)

(5,1)   (5,2)   (5,3)   (5,4)

i.e. the total outcomes are : 20

(a)

Let A denote the event that the first number is 4.

and B denote the event that the sum is: 9.

Let P denote the probability of an event.

We are asked to find:

               P(A|B)

We know that it could be calculated by using the formula:

P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}

Hence, based on the data we have:

P(A\bigcap B)=\dfrac{1}{20}

( Since, out of a total of 20 outcomes there is just one outcome which comes in A∩B and it is:  (4,5) )

and

P(B)=\dfrac{2}{20}

( since, there are just two outcomes such that the sum is: 9

(4,5) and (5,4) )

Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

(b)

Let A denote the event that the first number is 3.

and B denote the event that the sum is: 8.

Let P denote the probability of an event.

We are asked to find:

               P(A|B)

Hence, based on the data we have:

P(A\bigcap B)=\dfrac{1}{20}

( since, the only outcome out of 20 outcomes is:  (3,5) )

and

P(B)=\dfrac{2}{20}

( since, there are just two outcomes such that the sum is: 8

(3,5) and (5,3) )

Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

7 0
3 years ago
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