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3 years ago

17+36=z-37 what is z

Mathematics

1 answer:

Roman55 [17]3 years ago

5 0

Answer:

Its 90

Step-by-step explanation:

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Brenda has 3 apples and tila has 5 bananas how many more bananas are there then apples

galben [10]

Answer:2

Step-by-step explanation: 5 - 3 = 2

8 0

3 years ago

For each rational expression, identify the greatest common factor, write the expression in factored form, and simplify.

podryga [215]

Answer:

1) $9a,\frac{3^{3n}}{5^{n^{5}}},\frac{x+x^{3}}{x^{3}},\frac{a}{a^{5}-1},\frac{3b+1}{5b^{3}}, \frac{3y}{y^{2}-2},\frac{2x^{2}+4x-1}{3}, \frac{(p^{4}-5q^{2})}{(2p^{2}q^{3}+6p^{4}q^{2})}$ 2) $\frac{xy^{4}+7x^{5}y^{2}+49}{2x^{5}y^{2}}$

Prime factorize the parameters 7,49,28,343 pick its GCF=7. As for the variables choose the ones raised to the least exponent and divide each term by this.

Then, after that part. All that's left is a simplification dividing the members by the common monomial.

Step-by-step explanation:

1) Let's proceed this way. For the numbers, to find the GCF is simply to Prime factor the numbers and pick greatest common factor. When it comes to variables the point is to choose the variable with the least exponent.

$\frac{27a^{4}}{3a^{3}}\: GCF=3a^{3}\Rightarrow \frac{27a^{4}:3a^3}{3a^{3}:3a^{3}}=9a\\\\\frac{15m^{5n}}{25m^{2n^{6}}}\:GCF=5 \Rightarrow \frac{15m^{5n}:5m^{2n}}{25m^{2n^{6}}:5m^{2n}}=\frac{3^{3n}}{5^{n^{5}}}\\\\\frac{x^{4}+x^{6}}{x^{3}}\:GCF=x^3\Rightarrow \frac{x^{4}:x^{3}+x^{6}:x^{3}}{x^{3}:x^{3}}\Rightarrow \frac{x+x^{3}}{x^{3}}$

$\frac{a^{5}}{a^{9}-a^{4}}\:GCF:a^{4}\Rightarrow \frac{a^{5}:a^{4}}{a^{9}:a^{4}-a^{4}:a^{4}}\Rightarrow \frac{a}{a^{5}-1}\:or\:\frac{a^{4}(a)}{a^{4}(a^{5}-1)}=\frac{a}{a^{5}-1}\\\frac{3b^{2}+b}{5b^{4}}\:GCF=b\Rightarrow \frac{b(3b+1)}{b(5b^{3})}=\frac{3b+1}{5b^{3}}\\\frac{21y^{3}}{7y^4-14y^2}\:GCF=7y^{2}\Rightarrow \frac{7y^{2}(3y)}{7y^{2}(y^{2}-2)}\Rightarrow \frac{3y}{y^{2}-2}$

$\frac{6x^{4}+12x^{3}-3x^{2}}{9x^{2}}\:GCF=3x^{2}\Rightarrow \frac{3x^{2}(2x^{2}+4x-1)}{3x^{2}(3)}\Rightarrow \frac{2x^{2}+4x-1}{3}$

$\frac{2p^{5}q-10pq^{3}}{4p^{3}q^{4}+12p^{5}q^{3}}\:GCF=2pq \Rightarrow \frac{2pq(p^{4}-5q^{2})}{2pq(2p^{2}q^{3}+6p^{4}q^{2})}=\frac{(p^{4}-5q^{2})}{(2p^{2}q^{3}+6p^{4}q^{2})}$

2,3) Write your own example of a rational expression and demonstrate how to simplify the expression using GCF (greatest common factor).

Write a rational expression with a gfc that has both a numeric part and a variable part.

Identify gfc and show how to simplify using gfc.

Well, similarly, to the previous ones. Prime factorize the parameters 7,49,28,343 pick its GCF=7. As for the variables choose the ones raised to the least exponent and divide each term by this.

Then, after that part. All that's left is a simplification dividing the members by the common term as it follows:

$\frac{7x^{2}y^{6}+49x^{6}y^{4}+343xy^{2}}{28x^{6}y^{4}}\Rightarrow GCF=7xy^{2}\Rightarrow \frac{7xy^{2}(xy^{4}+7x^{5}y^{2}+49)}{7xy^{2}(2x^{5}y^{2})}\Rightarrow \frac{xy^{4}+7x^{5}y^{2}+49}{2x^{5}y^{2}}$

3 0

3 years ago

No link answer please help im stuck

Tasya [4]

Answer:

not sure it says error when i try to look at the link

5 0

3 years ago

15 + 5m = 415 Can you help me find m?

Ann [662]

All you have to do is isolate m. We have to move all terms except m to the other side.

15 + 5m = 415

We have to cancel out the numbers. 15 is being added so we subtract it from both sides.

15 - 15 + 5m = 415 - 15

5m = 400

5 is being multiplied so we divide it on both sides.

5m/5 = 400/5
m = 80

We can plug in to prove.

15 + 5(80) = 415

15 + 400 = 415

415 = 415

6 0

3 years ago

Enrollment in a school district is currently 1250 students and is decreasing at approximately 3% per year. Enter the number of y

FromTheMoon [43]

Answer: the number of years is 7.3 years

Step-by-step explanation:

We would apply the formula for exponential decay which is expressed as

A = P(1 - r)^ t

Where

A represents the population after t years.

t represents the number of years.

P represents the initial population.

r represents rate of growth.

From the information given,

P = 1250

A = 1000

r = 3% = 3/100 = 0.03,

Therefore

1000 = 1250(1 - 0.03)^t

1000/1250 = (0.97)^t

0.8 = 0.97^t

Taking log of both sides, it becomes

Log 0.8 = tLog 0.97

- 0.0969 = - 0.0132t

t = - 0.0969/- 0.0132t

t = 7.3 years

4 0

3 years ago