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galben [10]
3 years ago
8

Name the character encoding standard that enables up to 128 different commonly used characters,

Computers and Technology
1 answer:
Lelechka [254]3 years ago
8 0

Answer:

ASCII character set.

Explanation:

ASCII is an acronym for American Standard Code for Information Interchange and it was developed from a telegraph code. It is typically a character encoding standard that comprises of seven-bit (7-bit) set of codes.

ASCII character set is the character encoding standard that enables up to 128 different commonly used characters, numbers and symbols to be used in electronic communication systems. The ASCII character set is only used for encoding English language and it comprises of both the lower case and upper case letters of the 26 alphabets, number 0 to 9 and symbols.

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Largest of five (5 points). Write an algorithm that read 5 distinct integers and displays the largest value. Assume the input va
mrs_skeptik [129]

Answer:

import java.io.*;

public class Larger {

  public static void main(String[] args) throws IOException{

       BufferedReader br=new BufferedReader(new InputStreamReader(System.in));// reading input from buffered reader

        int a,max=-99999,i;

        for(i=1;i<=5;i++)

        {

            a=Integer.parseInt(br.readLine());//converting string input string to int

            if(a >max)

               max=a;

         

        }

       System.out.println("Maximum value : "+max);

  }

Explanation:

6 0
3 years ago
Which of the following is an advantage of batch processing?
alina1380 [7]

Answer:

it can balance computing resources by time

Explanation:

this this is as it involves multiprogramming

8 0
3 years ago
We will use linear interpolation in a C program to estimate the population of NJ between the years of the census, which takes pl
nikklg [1K]

Answer:

See explaination for program code

Explanation:

program code below:

#include<stdio.h>

int main()

{

//file pointer to read from the file

FILE *fptr;

//array to store the years

int years[50];

//array to store the population

float population[50];

int n = 0, j;

//variables for the linear interpolation formula

float x0,y0,x1,y1,xp,yp;

//opening the file

fptr = fopen("njpopulation.dat", "r");

if (fptr != NULL)

{

//reading data for the file

while(fscanf(fptr, "%d %f", &years[n], &population[n]) == 2)

n++;

//prompting the user

int year = -1;

printf("Enter the years for which the population is to be estimated. Enter 0 to stop.\n\n");

while(year != 0)

{

printf("Enter the year (1790 - 2010) : ");

scanf("%d", &year);

if (year >= 1790 && year <= 2010)

{

//calculating the estimation

xp = year;

for (j = 0; j < n; j++)

{

if (year == years[j])

{

//if the year is already in the table no nedd for calculation

yp = population[j];

}

else if (j != n - 1)

{

//finding the surrounding census years

if (year > years[j] && year < years[j + 1])

{

//point one

x0 = years[j];

y0 = population[j];

//point two

x1 = years[j + 1];

y1 = population[j + 1];

//interpolation formula

yp = y0 + ((y1-y0)/(x1-x0)) * (xp - x0);

}

}

}

printf("\nEstimated population for year %d : %.2f\n\n", year, yp);

}

else if (year != 0)

{

printf("\nInvalid chioce!!\n\n");

}

}

printf("\nAborting!!");

}

else

{

printf("File cannot be opened!!");

}

close(fptr);

return 0;

}

OUTPUT :

Enter the years for which the population is to be estimated. Enter 0 to stop.

Enter the year (1790 - 2010) : 1790

Estimated population for year 1790 : 184139.00

Enter the year (1790 - 2010) : 1855

Estimated population for year 1855 : 580795.00

Enter the year (1790 - 2010) : 2010

Estimated population for year 2010 : 8791894.00

Enter the year (1790 - 2010) : 4545

Invalid chioce!!

Enter the year (1790 - 2010) : 1992

Estimated population for year 1992 : 7867020.50

Enter the year (1790 - 2010) : 0

Aborting!!

5 0
3 years ago
Create a Python program in a file named loops1.py that does the following: a. Use a while loop to keep asking the user for input
Rashid [163]

Answer:

mystr = input("Enter a string ")

length = len(mystr)

while length<10:

   mystr = input("Enter a string ")

   length = len(mystr)

   if(length>=10):

       break

if len(mystr)%2==0:

   print(mystr.lower())

else:

   print(mystr.upper())

Explanation:

The variable mystr is used to save user's input which is received with the input function

A second variable length is used to save the length of the input string Using a while statement the user is continually prompted to enter a string while length is less than 10.

If length is greater or equal to 10. We check for even or odd using the modulo (%) operator.

We use lower() and upper() to change the case of the string

7 0
3 years ago
Read 2 more answers
When code is compiled it
lesantik [10]

Answer:

A compiler takes the program code (source code) and converts the source code to a machine language module (called an object file). Another specialized program, called a linker, combines this object file with other previously compiled object files (in particular run-time modules) to create an executable file. In short, it's A or D.

5 0
3 years ago
Read 2 more answers
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