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Norma-Jean [14]
3 years ago
14

Camille placed blocks on a table in rows and columns. All the rows and columns had the same

Mathematics
1 answer:
dexar [7]3 years ago
7 0
If all the rows and columns have the some number of blocks, then

(number of blocks in each row) times (number of blocks in each column)

must be a perfect square.

'121' is the only choice on the list that's a perfect square.  It's the square of 11.
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Which three side lengths best describe the triangle in the diagram?
Sunny_sXe [5.5K]

Answer:

d. 6cm, 6cm, 6cm

Step-by-step explanation:

each one of the rulers is lined correctly and shows that it is 6 cm

8 0
2 years ago
Robin invests $3,210 in an account that is compounded annually and pays
igor_vitrenko [27]

Answer:

the factor is an increasing value of 17/332 or the power of pointed answers of interest of 3.4% which makes it aroujd 2 but doesnt matter because its the factor and not issued investment

Step-by-step explanation:

8 0
3 years ago
A hose fills a hot tub at a rate of 3.13 gallons per minute. How many hours will it take to fill a 255-gallon hot tub?
GalinKa [24]

Answer:

about 1.4 hours

Step-by-step explanation:

3.13 gallons per minute.

60 minutes in an hour, so multiply both numbers by 60.

187.8 gallons per hour.

Divide the number of gallons we need to fill the tub the number of gallons put in per hour.

255÷187.8=1.375...

Round it, you get 1.4 hours.

It takes about 1.4 hours to fill the hot tub.

6 0
3 years ago
Jared made 4 bird houses in 3 days. How many days will it take him to make 28 bird houses.
pogonyaev
4 times 7 = 28

3 times 7 = 21

It will take him 21 days to make 28 bird houses.
6 0
3 years ago
The limit as h approaches 0 of (e^(2+h)-e^2)/h is ?
Whitepunk [10]
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h

</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
3 0
3 years ago
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