The answer is zach on Monday
Hope this helped!
Xy = 6
x = 2
2y = 6
y = 6÷2
y = 3
x + y = (2) + (3) = 5
A function and its inverse are reflected over the line y = x. To graph a function and its inverse, all you have to do is graph the function and then switch all x and y values in each point to graph the inverse.
The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is
(x - x^2)^2 * sqrt(3)/4.
Integrating from x = 0 to x = 1, we have
[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4
= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144.
Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...
No, it is not a solution, as 15 is not less-than fifteen.<span />
