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3 years ago

State the name of the property illustrated below.

Mathematics

1 answer:

ivanzaharov [21]3 years ago

8 0

Answer:

Step-by-step explanation:

This is the associative property for addition. In informal language, it says under addition, the order of the addition is not critical.

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What is the slope of a line that is perpendicular to a line whose equation is 7y=-3x+2 ?

____ [38]

1/3x because the slope have the opposite reciprocal of -3x

4 0

4 years ago

An airplane is flying at a height of 5 kilometers above the ground. The distance along the ground from the airplane to the airpo

Cerrena [4.2K]

$\rule{70mm}{2.9pt}$

$\large \sf{✟ \: Problem \: ✟} :$

An airplane is flying at a height of 5 kilometers above the ground. The distance along the ground from the airplane to the airport is 7 kilometers. What is the angle of depression from the airplane to the airport? (Write the answer to the nearest degree.)

$\rule{70mm}{2.9pt}$

$\large \sf{✟ \: Solution \: ✟} :$

✞ Step 1 ✞: Identify what is asked in the problem.

❒ The angle of depression from the airplane to the airport.

✞ Step 2 ✞: Use appropriate trigonometric ratio to solve the problem.

❒ Since the two legs of the right triangle are part of the problem, hence we use tangent ratio:

$\qquad \qquad \bigstar \: \: \boxed{\tt{ \quad \tan A \degree = \frac{5}{7} \quad}}$

✞ Step 3 ✞: Solution and interpretation.

$: \qquad \large \implies \tt{ \tan A = \frac{5}{7} }$

$: \qquad \large \implies \tt{A = \tan^{ - 1}(\frac{5}{7} )}$

$: \qquad \large \implies \tt{A = 35.54 \approx \pmb{36 \degree}}$

$\rule{70mm}{2.9pt}$

$\large \sf{✟ \: Answer \: ✟} :$

Hence, the angle of depression from the airplane to the airport is approximately 36°.

$\rule{70mm}{2.9pt}$

$\large \bold{✰ \: MrHarold \: ࿐}$

8 0

2 years ago

Use any pair of points to calculate the slope of the line.

natima [27]

<u>Answer:</u>

Using the pair of points (1, 1) and (0, 0) we have calculated the slope of the line

<u>Solution:</u>

Given that, we can use any two points from cartesian plane,

Let the two points be (0, 0) and (1, 1)

We have to find the slope of the line that, passes through the chosen two points.

Now, we know that, slope of a line that passes through $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)$ is given by:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\text { Here in our problem, } x_{1}=0, y_{1}=0, x_{2}=1 \text { and } y_{2}=1$

Substitute these values in "m" formula,

$\mathrm{m}=\frac{1-0}{1-0}=\frac{1}{1}=1$

Hence, the slope of the line that passes through (1, 1) and (0, 0) is 1.

4 0

3 years ago

How do i solve this?

Trava [24]

Answer:

Step-by-step explanation:

so first you take the 2 to the 1/4 power and put it in a radical expression so now it is the fourth root of 2 $\sqrt{2}$ but with a little four just like the expression at the end now you still have the 3 power left but $2^{3}$ is 8

8 0

3 years ago

I need help from a smart person

Savatey [412]

The answer would be
x>5

6 0

3 years ago