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masha68 [24]
3 years ago
5

The movie theater sells a total of 100 tickets and makes a total of $880. If the theater charges $6 per child's ticket and $10 p

er adult's ticket. How many of each type of ticket did they sell?
Mathematics
1 answer:
lutik1710 [3]3 years ago
8 0

Answer:the number of children tickets that were sold is 30.

the number of adult tickets that were sold is 70

Step-by-step explanation:

Let x represent the number of children tickets that were sold.

Let y represent the number of adult tickets that were sold.

The movie theater sells a total of 100 tickets. This means that

x + y = 100

The theater charges $6 per child's ticket and $10 per adult's ticket. The movie theater made a total of $880. It means that

6x + 10y = 880 - - - - - - - - - - -1

Substituting x = 100 - y into equation 2, it becomes

6(100 - y) + 10y = 880

600 - 6y + 10y = 880

- 6y + 10y = 880 - 600

4y = 280

y = 280/4 = 70

x = 100 - y = 100 - 70

x = 30

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Fredericka can make 65% of her shots from the free-throw line. if she shoots 75 times, how many shots can she expect to go in?
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Roll one fair, six-sided die, numbered 1 through 6. Let A be the event you will roll an even number. Let B be the event you will
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a) not independent

b) not mutually exclusive

Step-by-step explanation:

Given:

- A 6 sided die is rolled

- Event A is rolling an even number

- Event B is rolling a prime number

Find

- (a) Are A and B independent events?

- (b) Are A and B mutually exclusive events?

Solution:

- We will find the probability of each event:

                       set(Even number: A) = {2, 4, 6} = 3 outcomes

                       set(Prime number: B) = {2 , 3, 5} = 3 outcomes

- The probabilities are:

                        P(A) = 3/6 = 0.5

                        P(B) = 3/6 = 0.5

- For Event A and B to be independent then the following condition must match:

                        P ( A & B ) = P(A)*P(B)

                        set (A&B) = {2} = 1 outcome

                        P(A&B) = 1/6

                        1 / 6 = 0.5*0.5

                        1/6 = 0.25         ...... NOT INDEPENDENT

- For Event A and B to be mutually exclusive then the following condition must match:

                        P(A&B) = 0

                        P(A&B) = 1/6

Hence, we can say the events are NOT MUTUALLY EXCLUSIVE

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3 years ago
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