Answer:
The volume of the figure is ![(\frac{l^{3}}{3})[\frac{\pi }{2}-1]\ units^{3}](https://tex.z-dn.net/?f=%28%5Cfrac%7Bl%5E%7B3%7D%7D%7B3%7D%29%5B%5Cfrac%7B%5Cpi%20%7D%7B2%7D-1%5D%5C%20units%5E%7B3%7D)
Step-by-step explanation:
we know that
The volume of the figure is equal to the volume of the cone minus the volume of the square pyramid
step 1
Find the volume of the cone
The volume of the cone is equal to
we have
----> the diagonal of the square base of pyramid is equal to the diameter of the cone
substitute
step 2
Find the volume of the square pyramid
The volume of the pyramid is equal to
where
B is the area of the base
h is the height of the pyramid
we have
substitute
step 3
Find the volume of the figure
![\frac{1}{6}\pi (l)^{3}\ units^{3}-\frac{1}{3}l^{3}\ units^{3}=(\frac{l^{3}}{3})[\frac{\pi }{2}-1]\ units^{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%7D%5Cpi%20%28l%29%5E%7B3%7D%5C%20units%5E%7B3%7D-%5Cfrac%7B1%7D%7B3%7Dl%5E%7B3%7D%5C%20units%5E%7B3%7D%3D%28%5Cfrac%7Bl%5E%7B3%7D%7D%7B3%7D%29%5B%5Cfrac%7B%5Cpi%20%7D%7B2%7D-1%5D%5C%20units%5E%7B3%7D)
Answer:
Step-by-step explanation:
We'll use the standard equation y=mx+b to solve this problem. m is the slope of the line and b is the y intercept.
We know the slope, but we have to solve for the y intercept. To do this (I mean solve for 'b'), we need to know the slope, x value, and y value. We know the slope (-2/3), x= -3, and y=8. Let's plug this into y=mx+b and solve for b.
Let's plug all of this back into the first equation y=mx+b.
That's the answer to this problem.
I hope this helps.
Answer:
3x+2y+2=0
3x=-2y-2
x=-(2y+2)/3
Step-by-step explanation:
Answer:
100 pi cm^2
or approximately 314 cm^2
Step-by-step explanation:
The surface area of a sphere is given by
SA = 4 pi r^2
The radius is 5
SA = 4 *pi * 5^2
SA = 4*pi(25
SA = 100 pi cm^2
If pi is 3.14
SA = 100 *3.14 = 314 cm^2
Answer:
segment BC is located at B (1, 0) and C (1, 3) and is one-half the size of segment B C .
