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bogdanovich [222]
3 years ago
14

What is the benefit of using expressions in math?

Mathematics
2 answers:
atroni [7]3 years ago
8 0

Answer:

To help you understand the problem with out actually doing the work, you are just writing it out.

Step-by-step explanation:

Greeley [361]3 years ago
5 0

Answer:

The benefits of using expressions in math is to know what you are supposed to be using to solve your problem. Expression area good use too also for word problems!!

Step-by-step explanation:

<u><em>Plz mark Brainlist!!!</em></u>

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The diameter d in inches of a rope required to lift a weight of w tons is given by the function d = 10w/ π . How much weight can
Ilia_Sergeevich [38]

Answer:

Option D) 1.26 tons

Step-by-step explanation:

we have

d=\frac{10w}{\pi}

where

d is the diameter of a rope in inches

w is the weight in tons

we have

d=2(2)=4\ in ----> the diameter is two times the radius

substitute the value of d and solve for w

4=\frac{10w}{\pi}

w=\frac{4\pi}{10}=0.4\pi\ tons

assume

\pi =3.14

0.4(3.14)=1.26\ tons

7 0
4 years ago
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vichka [17]
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4 years ago
Mercury travels about 107,100 miles per hour as it resolves around the sun. How far does Mercury travel in 6 seconds?
Anni [7]

Answer:

12

Step-by-step explanation:

8 0
3 years ago
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A man invests his savings in two accounts, one paying 6% and the other paying 10% simple interest per year. He puts twice as muc
Masteriza [31]

Let x represent amount invested in the higher-yielding account.

We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be 2x.

We are also told that his annual interest is $6600 dollars. We know that annual interest for one year will be principal amount times interest rate.

I=Prt, where,

I = Amount of interest,

P = Principal amount,

r = Annual interest rate in decimal form,

t = Time in years.

We are told that interest rates are 6% and 10%.

6\%=\frac{6}{100}=0.06

10\%=\frac{10}{100}=0.10

Amount of interest earned from lower-yielding account: 2x(0.06)=0.12x.

Amount of interest earned from higher-yielding account: x(0.10)=0.10x.

0.12x+0.10x=6600

Let us solve for x.

0.22x=6600

\frac{0.22x}{0.22}=\frac{6600}{0.22}

x=30,000

Therefore, the man invested $30,000 at 10%.

Amount invested in the lower-yielding account would be 2x\Rightarrow 2(30,000)=60,000.

Therefore, the man invested $60,000 at 6%.

8 0
3 years ago
Can someone help me with number 18 please
Akimi4 [234]
I got it its  this answer i used mathpapa for this
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