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sdas [7]
3 years ago
9

What is the slope? I need help plz

Mathematics
1 answer:
PIT_PIT [208]3 years ago
7 0

I don’t exactly know what you’re asking so if it is wrong I am so sorry.

The slope would be + $2.50 every 5 minutes.

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X-3<-12 Choose the correct graph for the inequality?
olga55 [171]
The correct graph is the last one
x -3<-12
x<-12+3
x<-9
7 0
3 years ago
Madison made the following table to record the height of each person in her family. If Madison and Jade lay end to end, how far
vitfil [10]

Answer:

10 ft

Step-by-step explanation:

To get their total reach, we add the two numbers.

 5⅙

+4⅚

Add integers and fractions

 5⅙

<u>+4⅚ </u>

 9⁶/₆

Convert the fraction to an integer

⁶/₆ = 1

Add the 1 to the 9

9 + 1 = 10 ft

If Madison and Jade lay end to end, they will they reach 10 ft.

6 0
3 years ago
Wal-Mart conducted a study to check the accuracy of checkout scanners at its stores. At each of the 60 randomly selected Wal-Mar
Mamont248 [21]

Answer:

a

The 95% confidence interval is

   0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

b

  Generally  99% is outside the interval obtained in a  above then the claim of Wal-mart is not believable  

c

 n =  125  \  stores  

Step-by-step explanation:

From the question we are told that

    The sample size is  n =  60  

    The number of stores that had more than 2 items price incorrectly is  k =  52  

   

Generally the sample proportion is mathematically represented as  

             \^ p  =  \frac{ k }{ n }

=>          \^ p  =  \frac{ 52 }{ 60 }

=>          \^ p  =  0.867

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

=>   E =  1.96  * \sqrt{\frac{ 0.867  (1- 0.867)}{60} }

=>   E =  0.0859

Generally 95% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

=>    0.867  - 0.0859  <  p <  0.867  +  0.0859

=>    0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

Considering question b

Generally  99% is outside the interval obtained in a  above then the claim of Wal-mart is not believable  

   

Considering question c

From the question we are told that

    The margin of error is  E = 0.05

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the sample size is mathematically represented as  

    n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=> n=  [\frac{1.645 }}{0.05} ]^2 * 0.867  (1 - 0.867 )

=>   n =  125  \  stores  

4 0
3 years ago
URGENTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT
mash [69]

Answer:

I don't think soo that it make a function

4 0
2 years ago
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padilas [110]
The answer is A i think
5 0
2 years ago
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