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Ahat [919]
3 years ago
15

What is the area of an equilateral triangle that has 2 yards and a height of 4.25 ft?

Mathematics
1 answer:
RUDIKE [14]3 years ago
5 0
The first thing you need to do is convert the yards into feet. In one yard there are three feet. So 2*3=6 now you can do the triangle area equation. 6*4.25=25.5 then divide by two. 25.5/2=12.75So the area of the triangle is 12.75 ft^2Hope this helps
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Solve the following equation. Then place the correct number in the box provided.
solong [7]
X should be 7 after doing all the calculation.
5 0
3 years ago
1. Mark each of the following graphs as (a) a function, but not one-to-one, (b) one-to-one function, or (c) not a function. In e
Helen [10]

Answer:

  (a) a function, but not one-to-one

Step-by-step explanation:

The graph is of a function if it passes the vertical line test: a vertical line intersects the graph in at most 1 point.

The function is one-to-one if it passes the horizontal line test: a horizontal line intersects the graph in at most 1 point.

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Here, the graph consists of a series of non-overlapping horizontal lines. It passes the vertical line test (is a function), but a horizontal line can intersect the graph in an infinite number of points (is not one-to-one).

The graph is a function, but not one-to-one.

6 0
2 years ago
the art teacher found 3 boxes of brushes and 4 extras brushes. There were 40 brushes in all. how many brushes were in each box
natita [175]
3 boxes times 40 = 120 + 3 = 143
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7 0
3 years ago
Read 2 more answers
April shoots an arrow upward into the air at a speed of 32 feet per second from a platform that is 11 feet high. The height of t
dusya [7]

Answer:

27 ft

the maximum height of the​ arrow is 27 ft

Step-by-step explanation:

Given;

The height of the arrow is given by the function;

h(t) = -16t^2 + 32t + 11

Maximum height is at point when dh(t)/dt = 0.

Differentiating h(t), we have;

dh/dt = -32t + 32 = 0

Solving for t;

-32t = -32

t = -32/-32 = 1

t = 1 (time at maximum height is t = 1)

Substituting t=1 into h(t), to determine the value of maximum height;

h(max)= -16(1^2) + 32(1) + 11

h(max) = 27 ft

the maximum height of the​ arrow is 27 ft.

8 0
3 years ago
(HELP ME!!!!!!!!!!!!)
Kobotan [32]

The car is driving at 70 miles per hour which is above the speed limit on the highway

<h3 /><h3>Linear equation</h3>

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the slope of the line and m is the y intercept.

Let y represent the distance in miles and x represent the time in hours. Hence:

  • Using the points (0, 0) and (3, 200)

Slope = \frac{y_2-y_1}{x_2-x_1} =\frac{200-0}{3-0} =66.7

Bob speed limit is 66.7 miles per hour

Given a car by y = 70x. The car is driving at 70 miles per hour which is above the speed limit on the highway

Find out more on linear equation at: brainly.com/question/14323743

5 0
2 years ago
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