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2 years ago

2x - 7 = -X-1 What is that answer to this

Mathematics

1 answer:

denis23 [38]2 years ago

4 0

Answer:

x = 2

Step-by-step explanation:

2x - 7 = -x - 1

(add x on both sides)

3x - 7 = -1

(add 7 on both sides)

3x = 6

(divide both sides by 3)

x = 2

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What is the surface area of this design?

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Paga No. Date: 6. When a discount of 25% is allowed on the marked price then the selling price will be 1425 .lf the marked price

SVETLANKA909090 [29]

Answer:

The percentage loss = 10.9375 %

Step-by-step explanation:

Let the cost price = x

Since the marked price is 18.75% above the cost price so the

Marked price = 1.1875 x

When a discount of 25% is allowed on the marked price , the selling price will be Rs. 1425

⇒ Marked price × 0.75 = 1425

⇒ Cost price × ( 1.1875 × 0.75 ) = 1425

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2 years ago

ABCD- parallelogram, If the perimeter of Triangle CPQ is 15cm, Find the perimeter of triangle BAQ. Find the perimeter of triangl

melamori03 [73]

Answer:

The answer is below

Step-by-step explanation:

A parallelogram is a quadrilateral (has 4 sides and 4 angle) with two pair of parallel and opposite sides. Opposite sides of a parallelogram are parallel and equal.

Given parallelogram ABCD:

AB = CD = 18 cm; BC = AD = 8 cm

∠P = ∠P, ∠PDA = ∠PCQ (corresponding angles are equal).

Hence ΔPCQ and ΔPDA are similar by angle-angle similarity theorem. For similar triangles, the ratio of their corresponding sides equal. Therefore:

$\frac{CD}{PC}= \frac{AD}{CQ}\\\\\frac{18}{6}=\frac{8}{x} \\\\x=\frac{6*8}{18}=\frac{8}{3}\ cm$

Perimeter of CPQ = CP + CQ + PQ

15 = 6 + 8/3 + PQ

PQ = 15 - (6 + 8/3)

PQ = 6.33

∠CQP = ∠AQB (vertical angles), ∠QCP = ∠QBA (alternate angles are equal).

Hence ΔCPQ and ΔABQ are similar by angle-angle similarity theorem

$\frac{AQ}{QP}=\frac{AB}{CP} \\\\\frac{AQ}{6.33} =\frac{18}{6} \\\\AQ=\frac{18}{6}*6.33\\\\AQ = 19$

$\frac{BQ}{CQ}=\frac{AB}{CP} \\\\\frac{BQ}{8/3} =\frac{18}{6} \\\\BQ=\frac{18}{6}*\frac{8}{3} \\\\BQ =8$

Perimeter of BAQ = AB + BQ + AQ = 18 + 8 + 19 = 45cm

PA = AQ + PQ = 19 + 6.33 = 25.33

PD = CD + DP = 18 + 6 = 24

Perimeter of PDA = PA + PD + AD = 24 + 25.33 + 8 = 57.33 cm

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