Answer:
The equation of line with given slope that include given points is 3 y + x - 20 = 0
Step-by-step explanation:
According to Cora , if we know the slope and points on a line then we can write the equation of a line .
Since , The equation of line in slope-intercept form is
y = m x + c
<u>Where m is the slope of line , and if we know the points ( x , y ) which satisfy the line then constant term c can be get and the equation of line can be formed .</u>
So , From the statement said above it is clear that she is correct .
Now , Again
Given as :
Slope of a line is m = -
That include points ( 2 , 6 )
Now from the equation of line as y = m x + c
∴ 6 = - ( 2 ) + c
Or, 6 = - + c
So , c = 6 +
or, c =
∴ c =
So, The equation of line can be written as
y = - x +
Or, 3 y = - x + 20
I.e 3 y + x - 20 = 0
Hence The equation of line with given slope that include given points is 3 y + x - 20 = 0 Answer
Answer:
The answer is 1.
Step-by-step explanation:
The answer choice isn't even up there. The answer is 15. Since Because hit 22 home runs; you would just subtract to find the number of Beverly's home runs since it says "7 more home runs than Beverly".
22 - 7= 15.
Hopefully this helps
40% of the number 50 is 20
Answer:
The lines are parallel, with the same slope of 5.
Step-by-step explanation:
Remember that if slopes are the same, then the lines are parallel. If the slopes are opposite reciprocals, they are perpendicular. If they are neither of those cases, then they would be neither.
1) Since y = 5x + 1 is already in slope-intercept format (y = mx + b, in which m represents the slope) we know that 5 is the slope of that equation.
2) To find the slope of -5x + y = 6, let's just convert it to the slope-intercept format by isolating y on the left side like so:
(All you need to do is move -5x to the right side of the equation.) So, by looking at y = 5x + 6, we can do the same thing we did from step 1 and find that the slope is 5.
3) Since both of the equations' slopes are 5, they share the same slope - therefore, they are parallel.
Hope this helps! Please do not hesitate to ask any questions.