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Lana71 [14]
3 years ago
5

Evaluate the following expression when x = 6 and y = 2:

Mathematics
1 answer:
Liula [17]3 years ago
5 0

Answer:

11/2

Step-by-step explanation:

\frac{ {x}^{2} +  {y}^{3}  }{2 + x}  \\

when,

x = 6 \\ y = 2

Now substitute the value we get,

\frac{ {6}^{2}  +  {2}^{3} }{2 + 6} \\  \\  =  \frac{36 + 8}{8}   \\  \\  =  \frac{44}{8} \\  \\  =  \frac{11}{2}

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Find the equation of a line that is perpendicular to 4x+6y=1 and that has a greater intercept to the line 2x+3y=18
enot [183]

Answer:

2y - 3x = -15

Step-by-step explanation:

Slope of the line 4x + 6y = 1 is as shown below;

Rewrite in slope intercept form;

6y = -4x+1

y = -4x/6 + 1/6

y = -2x/3 + 1/6

mx = -2/3x

m = -2/3

The slope of the line perpendicular M = -1/(-2/3)

M = 3/2

Get the x and y intercept of 2x+3y = 18

x intercept occurs when y  = 0

2x + 0 = 18

x= 18/2

x = 9

y intercept occurs when x  = 0

0 + 3y = 18

3y= 18

y = 18/3

y = 6

The line passes through the point (9,6)

Write the equation in point slope form

y - y0 = m(x-x0)

y - 6  = 3/2(x-9)

2(y-6) = 3(x-9)

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2y - 3x = -15

This gives the required equation

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3 years ago
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