Answer:
Step-by-step explanation:
You are being asked to compare the value of a growing infinite geometric series to a fixed constant. Such a series will always eventually have a sum that exceeds any given fixed constant.
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<h3>a)</h3>
Angelina will get more money from the Choice 1 method of payment. The sequence of payments is a (growing) geometric sequence, so the payments and their sum will eventually exceed the alternative.
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<h3>c)</h3>
For a first term of 1 and a common ratio of 2, the sum of n terms of the geometric series is given by ...
Sn = a1×(r^n -1)/(r -1) . . . . . . . . . . series with first term a1, common ratio r
We want to find n such that ...
Sn ≥ 1,000,000
1 × (2^n -1)/(2 -1) ≥ 1,000,000
2^n ≥ 1,000,001 . . . . add 1
n ≥ log(1,000,001)/log(2) . . . . . take the base-2 logarithm
n ≥ 19.93
The total Angelina receives from Choice 1 will exceed $1,000,000 after 20 days.
15% of 45.4=6.81 this is the final answer
Answer:
a) The probability that 71 of 150 will prefer boy child is 71/150 or 0.47
b) The result contradicts the poll actual percentage is 47.33% which is 3.33% more than the poll predicted
Step-by-step explanation:
If 71 out of 150 prefer boy child
The probability that the 71 will prefer boy child is
= 71/150
The actual percentage is
(71/150)*100%
= 47.33%
This contradicts the poll as this is more than the poll predicted. That means Less than 71 of 150 actually preferred boy child.
Sheila will add 8 ounces of yellow paint to the mixture
