$=(a^2-10a)-(b^2+6b) +16$
$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$
$=(a-5)^2-25-(b+3)^2+9+16$
$=(a-5)^2-(b+3)^2$
If Aaron tunes into his favorite radio station at a randomly selected time, there is a 0.20 probability that a commercial will b
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<span>By the Pythagorean theorem
AB = </span>√(12²+5²) = √169 = 13 units
AB = </span>√(12²+5²) = √169 = 13 units