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nordsb [41]
2 years ago
14

Solve the system of equations using the elimination method. 4x+3y=16 x=-3y+13

Mathematics
2 answers:
Ipatiy [6.2K]2 years ago
7 0
Step by Step Solution
More Icon
System of Linear Equations entered :

[1] -4x - 3y = -7
[2] 16x - 3y = 13
Graphic Representation of the Equations :

-3y - 4x = -7 -3y + 16x = 13



Solve by Substitution :

// Solve equation [2] for the variable x


[2] 16x = 3y + 13

[2] x = 3y/16 + 13/16
// Plug this in for variable x in equation [1]

[1] -4•(3y/16+13/16) - 3y = -7
[1] - 15y/4 = -15/4
[1] - 15y = -15
// Solve equation [1] for the variable y


[1] 15y = 15

[1] y = 1
// By now we know this much :

x = 3y/16+13/16
y = 1
// Use the y value to solve for x

x = (3/16)(1)+13/16 = 1
Solution :
{x,y} = {1,1}
Gemiola [76]2 years ago
3 0

Answer:

 x=1   y=4

Step-by-step explanation:

1.  4x+3y=16

   x=-3y+13

2. 4x+3y=16

    x+3y=13

3.  4x+3y=16

     -x-3y=-13

4.  3x=3

5.   x=1

6. (1)=-3y+13

7.  1-13=-3y

8.   -12=-3y

9.    y=4

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Chapter : Algebra

Study : Math in Junior high school

x = 7 + √40

find √x of √x + 1

= √x + 1

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in Formula is :

= √7+√40 = √x + √y

= (√7+√40)² = (√x + √y)²

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= 7x - x² = 10

= x² - 7x + 10 = 0

= (x - 5)(x - 2) = 0

= x = 5 or x = 2

Subsitution x = 5 and x = 2, to equation 1

#For x = 5

= y = 7 - x

= y = 7 - (5)

= y = 2

#For x = 2

= y = 7 - x

= y = 7 - (2)

= y = 5

and his x and y was find :

#Equation 1 :

= x = 5 and y = 2

#Equation 2 :

= x = 2 and y = 5

So that :

√7+√40 = √x + √y

= √7+√40 = √2 + √5

And that is answer of question :

= √2 + √5 + 1

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