The perimeter of a rectangular playing field is 244 feet. If its length is 2 feet longer than twice its width, what are the dime
nsions of the field?
A. 20 ft./41 ft.
B. 21 ft./40 ft.
C. 40 ft./82 ft.
D. 42 ft./80 ft.
1 answer:
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.07Step-by-step explanation:
2xtimes 10 times 2
work shown above! basically each coordinate is opposite so the new coordinates would be A(0,-3) B(-2,4) C(4,6)
3< -5x+2x
3< -3x
-3x>3
3x> -3
X> -1
(1.636, 14.545) simply plug in the y=4x+8 into the second equation and then solve