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2 years ago

Solve log(2)6+log(3)5. Cant find instructions to remember how to do this

Mathematics

1 answer:

liq [111]2 years ago

5 0

The answer is 4.191786247582 see attached

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What's 5*(-2/3+3x) ?

sdas [7]

<span>5*(-2/3+3x)
= 15x - 10/3

hope it helps</span>

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3 years ago

Solve 10n^2+4n+15n+6

Allushta [10]

Answer:

Step-by-step explanation:

10n^2 +4n+15n+6 [Add the like terms]

10n^2 +19n +6

Hope this helps!

Mark brainliest if you think i helped! Would really appreciate!

4 0

3 years ago

evelyn rode her horse along a triangular path. The distance she traveled south was 5 times the distance she traveled east. Then

cricket20 [7]

(5x)^2 + x^2 = c^2

25x^2 + x^2 =c^2

sqrt 26 x ^ 2 = sqrt c^2

x sqrt 26= c

so answer is 6x + x sqrt 26

8 0

3 years ago

!!!PLEASE HELP I'LL GIVE BRAINLIEST AND 30 POINTS!!!

zepelin [54]

If two events are independent, then P(A and B) = P(A) x P(B).

In your situation, you need to solve 0.185 = 0.25 x P(B).

Can you take it from there?

8 0

2 years ago

Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.

galina1969 [7]

Answer:

All potential roots are 3,3 and $-\frac{5}{3}$ .

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

$f(x)=3x^3-13x^2-3x+45$

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

$p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45$

$q=\pm 1,\pm 3$

All possible roots

$\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}$

Now we check each rational root and see which are possible roots for given function.

$f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0$

$f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32$

$f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144$

$f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}$

Similarly, we will check for all value of p/q and we get

$f(-5/3)=0$

Thus, All potential roots are 3,3 and $-\frac{5}{3}$ .

5 0

2 years ago

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