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KonstantinChe [14]

3 years ago

14

Factor 54c–9d. Write your answer as a product with a whole number greater than 1

1 answer:

lisov135 [29]3 years ago

5 0

Answer:

9(6c - d)

Step-by-step explanation:

$54c - 9d \\ = 9 \times 6c - 9d \\ = 9(6c - d) \\$

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Which of these are the intercepts of the graph of y = 3x – 12?

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Y intercept is (0,-12), the x-intercept is (4,0)

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the graph of F(x), shown below in pink, has the same shape as the graph of G(x) = x^2, shown in gray. Which of the following is

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Consider a sample with data values of 27, 24, 21, 16, 30, 33, 28, and 24. Compute the 20th, 25th, 65th, and 75th percentiles. 20

densk [106]

Answer:

$P_{20} = 20$ --- 20th percentile

$P_{25} = 21.75$ --- 25th percentile

$P_{65} = 27.85$ --- 65th percentile

$P_{75} = 29.5$ --- 75th percentile

Step-by-step explanation:

Given

27, 24, 21, 16, 30, 33, 28, and 24.

N = 8

First, arrange the data in ascending order:

Arranged data: 16, 21, 24, 24, 27, 28, 30, 33

Solving (a): The 20th percentile

This is calculated as:

$P_{20} = 20 * \frac{N +1}{100}$

$P_{20} = 20 * \frac{8 +1}{100}$

$P_{20} = 20 * \frac{9}{100}$

$P_{20} = \frac{20 * 9}{100}$

$P_{20} = \frac{180}{100}$

$P_{20} = 1.8th\ item$

This is then calculated as:

$P_{20} = 1st\ Item +0.8(2nd\ Item - 1st\ Item)$

$P_{20} = 16 + 0.8*(21 - 16)$

$P_{20} = 16 + 0.8*5$

$P_{20} = 16 + 4$

$P_{20} = 20$

Solving (b): The 25th percentile

This is calculated as:

$P_{25} = 25 * \frac{N +1}{100}$

$P_{25} = 25 * \frac{8 +1}{100}$

$P_{25} = 25 * \frac{9}{100}$

$P_{25} = \frac{25 * 9}{100}$

$P_{25} = \frac{225}{100}$

$P_{25} = 2.25\ th$

This is then calculated as:

$P_{25} = 2nd\ item + 0.25(3rd\ item-2nd\ item)$

$P_{25} = 21 + 0.25(24-21)$

$P_{25} = 21 + 0.25(3)$

$P_{25} = 21 + 0.75$

$P_{25} = 21.75$

Solving (c): The 65th percentile

This is calculated as:

$P_{65} = 65 * \frac{N +1}{100}$

$P_{65} = 65 * \frac{8 +1}{100}$

$P_{65} = 65 * \frac{9}{100}$

$P_{65} = \frac{65 * 9}{100}$

$P_{65} = \frac{585}{100}$

$P_{65} = 5.85\th$

This is then calculated as:

$P_{65} = 5th + 0.85(6th - 5th)$

$P_{65} = 27 + 0.85(28 - 27)$

$P_{65} = 27 + 0.85(1)$

$P_{65} = 27 + 0.85$

$P_{65} = 27.85$

Solving (d): The 75th percentile

This is calculated as:

$P_{75} = 75 * \frac{N +1}{100}$

$P_{75} = 75 * \frac{8 +1}{100}$

$P_{75} = 75 * \frac{9}{100}$

$P_{75} = \frac{75 * 9}{100}$

$P_{75} = \frac{675}{100}$

$P_{75} = 6.75th$

This is then calculated as:

$P_{75} = 6th + 0.75(7th - 6th)$

$P_{75} = 28 + 0.75(30- 28)$

$P_{75} = 28 + 0.75(2)$

$P_{75} = 28 + 1.5$

$P_{75} = 29.5$

7 0

3 years ago

Given that R = 8 x + 4 y Find y when x = 8 and R = 30 Give your answer as an improper fraction in its simplest form.

Maksim231197 [3]

Answer:

y = -17/2

Step-by-step explanation:

Substitute with the givens.

30= 8(8) + 4y.

Multiply parentheses.

30 = 64 + 4y

Subtract.

30-64= -34

-34 = 4y.

Divide each side by 4.

y = - 8.5, or -17/2

hope that is right!

8 0

3 years ago

A soldier started patrolling around his camp at 22 30 . His patrol lasted 3 hours and 20 minutes .What time did his patrol end

baherus [9]

Answer:01 50 Hrs

Step-by-step explanation:

If the soldier started patrol at 2230 hrs and his petrol lasted for 3 hours and 20 minutes, that means he was on patrol for that time.

The time he finished was therefore:

= 2230 + 320

= 2550

At 24 you begin at 0:00am so:

= 2550 - 2400

= 150

Patrol ended at 0150 hrs

4 0

3 years ago