Question

There were 2430 Major League Baseball (MLB) games played in 2009, and the home team won in 54.9% of the games. If we consider the games played in 2009 as a sample of all MLB games, find and interpret a 90% confidence interval for the proportion of games the home team wins in Major League Baseball

Answer 1

Answer:

Confidence interval @ 90% = [0.5324 < p < 0.5656]

Step-by-step explanation:

We are given the following information:

Sample size (n) = 2430

Proportion of win (p) = 0.549

Proportion of loss (q) => 1-p = 0.451

By formula of confidence interval,

CI = p ± Z(90%) * $\sqrt{\frac{p*(1-p)}{n}}$ ,

CI = 0.549±(1.645* ((0.549*(0.451))/2430))^(0.5)

CI = [0.5324 < p < 0.5656]