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3 years ago

5

A marathon is a race that is 42.195 kilometers long. Joel ran two marathons this year. How many total kilometers did he run betw

een the two races?

2 answers:

nignag [31]3 years ago

8 0

84.39 is ya answer to the question

a_sh-v [17]3 years ago

7 0

Answer:

The answer is 84.384 kilometers.

Step-by-step explanation:

In order to determine the answer, we have to add the total amount of kilometers of each race.

The first marathon, Joel ran 42.195 kilometers.

The second marathon, Joel ran 42.195 kilometers again.

So, to determine the total, we can multiply 42.192 by two:

42.192*2=84.384

Finally, the total kilometers that Joel ran was 84.384.

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300 grams = 0.3 kilograms

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Airida [17]

Answer:

1. 35 2. 565.5 3. 12.28

Step-by-step explanation:

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3 years ago

A sporting goods store sells right-handed and left-handed baseball gloves. In one month, 12 gloves were sold for a total revenue

stepladder [879]

Answer:

$9$ right-handed gloves and $3$ left-handed gloves were sold.

Step-by-step explanation:

Given: In one month, $12$ gloves were sold for a total revenue of $\$561$ .

right-handed gloves cost $\$45$ and left-handed gloves cost $\$52$ .

To find: How much of each type of gloves did they sell?

Solution: Let they sell $x$ right-handed gloves, and $y$ left-handed gloves.

Now, cost of each right-handed gloves $=\$45$

cost of each left-handed gloves $=\$52$

Total revenue $=\$561$

So, we get

$45x+52y=561\:\:\:...(i)$

Also, in a month $12$ gloves were sold.

So, we get

$x+y=12\:\:\:...(ii)$

Now, from $(ii)$ we get, $x=12-y$ .

Putting $x=12-y$ in equation $(i)$ , we get

$45(12-y)+52y=561$

$\implies 540-45y+52y=561$

$\implies7y=561-540$

$\implies7y=21$

$\implies y=\frac{21}{7}$

$\implies y=3$

Now, putting $y=3$ in equation $(ii)$ , we get

$x+3=12$

$\implies x=12-3$

$\implies x=9$

Hence, $9$ right-handed gloves and $3$ left-handed gloves were sold.

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3 years ago

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Jobisdone [24]

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3 years ago

If sin a = - 4/5<br>and cos a > 0, find tan a and sec a.

Nina [5.8K]

Answer:

tan(a) = -4/3

sec(a) = 5/3

Step-by-step explanation:

sine is opposite over hypotenuse. so no we have a triangle with a hypotenuse of 5 and an opposite side relative to some angle a of -4. the hypotenuse is never negative.

so draw a right triangle, mark one of the non right angles as a then the side opposite to that is -4 and the hypotenuse is 5. use the pythagorean theorem to find the remaining angle. The result could be positive or negative, but the questions specifically tells us we want the positive version.

b^2 + -4^2 = 5^2

b = 3

tangent is opposite over adjacent. for a we know the opposite is 3now so tan(a) = -4/3

Now, secant is 1/cos, so lets find cos(a)

cos is adjacent over hypotenuse, and we jsut found the adjacent is 3. so cos(a) = 3/5

Now 1/cos(a) = hypotenuse over adjacent so 5/3

7 0

3 years ago