Busca dos números consecutivos de manera que la diferencia de sus cuadrados sea 19
1 answer:
The numbers are 9 and 10.
Let x be the first number. Since they are consecutive, this means (x+1) represents the second number.
The square of x is x². The square of (x+1) is
(x+1)²=(x+1)(x+1)=x²+1x+1x+1=x²+2x+1
The difference of these squares would be given by
x²+2x+1 - x²
Setting this equal to 19,
x²+2x+1 - x² = 19
Combining like terms,
2x+1=19
Subtract 1 from each side:
2x+1-1=19-1
2x=18
Divide both sides by 2:
2x/2 = 18/2
x = 9
The first number, x, is 9. This means the second number, x+1, is 9+1=10.
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