How much material is needed to construct a triangular tent that is 6 feet wide 4 feet tall and 8 feet long with side measurement
s of 5 feet?
1 answer:
Answer: 152ft^2
The amount of material needed to construct the tent is 152ft^2
Step-by-step explanation:
The amount of material needed to construct a triangular tent= the surface area of the triangular tent.
S.A = area of the 2 side rectangles + area of the 2 side triangles + area of the base.
S.A = Ab + At + Ar ....1
Area of the base Ab= Length × width = 8×6 = 48ft^2
Area of the two triangles At = 2 × 0.5 × width × height
At = width × height = 6×4 = 24ft^2
Area of the two rectangles Ar = 2 × side measurement × length
Side measurement is given as 5ft.
or it can be calculated using;
Side length can be calculated using Pythagoras theorem.
Examining the figure attached, we can see that;
Side breadth b = √(h^2 + (w/2)^2)
b = √(4^2 + (6/2)^2) = √(16+9) = √25
b = 5ft
Ar = 2×5×8 = 80ft^2
From eqn1, S.A can be solved as;
S.A = 48 + 24 + 80
S.A = 152ft^2
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