How much material is needed to construct a triangular tent that is 6 feet wide 4 feet tall and 8 feet long with side measurement
s of 5 feet?
1 answer:
Answer: 152ft^2
The amount of material needed to construct the tent is 152ft^2
Step-by-step explanation:
The amount of material needed to construct a triangular tent= the surface area of the triangular tent.
S.A = area of the 2 side rectangles + area of the 2 side triangles + area of the base.
S.A = Ab + At + Ar ....1
Area of the base Ab= Length × width = 8×6 = 48ft^2
Area of the two triangles At = 2 × 0.5 × width × height
At = width × height = 6×4 = 24ft^2
Area of the two rectangles Ar = 2 × side measurement × length
Side measurement is given as 5ft.
or it can be calculated using;
Side length can be calculated using Pythagoras theorem.
Examining the figure attached, we can see that;
Side breadth b = √(h^2 + (w/2)^2)
b = √(4^2 + (6/2)^2) = √(16+9) = √25
b = 5ft
Ar = 2×5×8 = 80ft^2
From eqn1, S.A can be solved as;
S.A = 48 + 24 + 80
S.A = 152ft^2
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Answer:
P = 0.006
Step-by-step explanation:
Given
n = 25 Lamps
each with mean lifetime of 50 hours and standard deviation (SD) of 4 hours
Find probability that the lamp will be burning at end of 1300 hours period.
As we are not given that exact lamp, it means we have to find the probability where any of the lamp burning at the end of 1300 hours, So we have
Suppose i represents lamps
P (∑i from 1 to 25 ( > 1300)) = 1300
= P(>
) where
represents mean time of a single lamp
= P (Z> ) Z is the standard normal distribution which can be found by using the formula
Z = Mean Time () - Life time of each Lamp (50 hours)/ (SD/
)
Z = (52-50)/(4/) = 2.5
Now, P(Z>2.5) = 0.006 using the standard normal distribution table
Probability that a lamp will be burning at the end of 1300 hours period is 0.006