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2 years ago

13

Alejandro kicks a football. The graph below shows the height of the football hh in meters after tt seconds. What is the football

’s greatest height?

1 answer:

mamaluj [8]2 years ago

4 0

Answer:

The answer will be 30.625 m

You might be interested in

A) the quantity in column A is larger

Crank

Answer: A

The number of distinctive prime factors in Column A is <u>60.</u>

The number of distinctive prime factors in Column B is <u>30.</u>

This number is 1/2 half more prime factors.

There is 30 more prime factors, so the answer is A.

The quantity in column A is larger than column B.

7 0

4 years ago

A factory is to be built on a lot measuring 210 ft by 280 ft. A local building code specifies that a lawn of uniform width and e

Tresset [83]

Answer:

Width of lawn = 35 ft

Dimensions of factory = length: 210 ft, width: 140 ft

Step-by-step explanation:

The total area of the lot can be calculated as:

$A_{lot} = 210 * 280\\A_{lot} = 58800 ft^{2}$

Since, the area of factory should be equal to area of lawn:

$A_{lot} = A_{factory} + A_{lawn}\\58800 = 2 A_{factory or lawn}\\\\A_{factory or lawn} = \frac{58800}{2}\\A_{factory or lawn} = 29400 ft^{2}$

Now, let 'x' be the width of lawn, the dimensions of factory can be written as:

$(210-2x)\\(280-2x)\\$

Since, area is equal to length x width:

$(210-2x)*(280-2x) = 29400\\Simplifying:\\210*280 - 210*2x - 2x*280 + 4x^{2} = 29400\\58800 - 420x - 560x +4x^{2} = 29400\\4x^{2} - 980x +58800 = 29400\\4x^{2} - 980x + 29400 = 0\\$

Divide whole equation by 4,

$x^{2} - 245 + 7350 = 0\\$

Solving above quadratic equation, we get,

$x = 210\\x = 35\\$

x = 35 seems realistic width of the lawn.

Now, finding the dimension of factory:

$(210-2x) = 210 - 2(35) = 140 ft\\(280-2x) = 280 - 2(35) = 210ft$

We can also reconfirm the area of factory by multiplying the above two lengths:

140 * 210 = 29400 ft

8 0

3 years ago

In the triangle below, Four-fifths represents which ratio?

vovangra [49]

Answer:

(A) $sin C =\frac{4}{5}$

Step-by-step explanation:

Opposite,AB = 4,

Hypotenuse,BC = 5

Adjacent, AC = 3.

$sin \theta =\frac{opposite}{Hypotenuse}\\ sin C =\frac{4}{5}$

8 0

4 years ago

4. A bag contains five red marbles, two orange marbles, one yellow marble, and two green marbles. Two marbles are drawn from the

Vitek1552 [10]

Answer:

C. 0.08889

Step-by-step explanation:

<u>Total number of marbles:</u>

5 + 2 + 1 + 2 = 10

<u>There are two possibilities</u>

Orange then green or green the orange

<u>The probabilities are:</u>

P(o&g) = 2/10*2/9 = 2/45
P(g&o) =2/10*2/9 = 2/45

<u>Required probability is:</u>

P = 2/45*2 = 4/45 = 0.08889

Correct choice is C

4 0

3 years ago

Write an equivalent expression,

nekit [7.7K]

Distribute the -2(6)-2(7g)=-12-14g

6 0

3 years ago