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Anon25 [30]
4 years ago
8

Can we declare top level classes as private or protected?

Computers and Technology
1 answer:
uysha [10]4 years ago
5 0

Answer and Explanation:

top level class can not be declare as private or protected. It is always public. If we declare a top level class as private then the compiler always complain that the  private is not allowed  and if we declare top level class as protected then compiler complain that modifier protection is not allowed here. so we can not declare top level class as private or protected

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A network administrator receives a call from the sales department requesting ports 20 and 21 be opened on the company’s firewall
emmainna [20.7K]

Answer:Document the reason for the request, Follow the company’s approval process for the implementation

Explanation:

The port 20 and 21 are used for the FTP connection, so before opening port 20 and 21 it is necessary to abide by the company data security policy which includes documenting the reason for the request and following company's approval process for its implementation.

8 0
3 years ago
Rutherford concluded from his calculations that the volume of an atom is filled with protons, neutrons and electrons. is mostly
enyata [817]

Answer:

The answer is "is mostly empty space".

Explanation:

In the given question option numbers is defined, so the explanation to this question  as follows:

The volume of an element holds one mole at high temperatures. The nuclear mass is usually indicated by mole: cc/mol in the \ cm^3. It is also known as a quantity, in which the same molecule was the measured values based on atomic mass as well as the thickness of both, and certain alternatives were wrong which can be explained as follows:

  • atom doesn't fill the protons, neutrons, and electrons.
  • It can't revolve with outside atoms and electrons.

6 0
3 years ago
Two technicians are discussing the lower-end operation of an engine. Technician A says that power loads result from the expansio
notka56 [123]

Answer:

It's Both are correct.

Explanation:

I've taken test

6 0
3 years ago
CS160 Computer Science I In class Lab 10
lianna [129]

Answer:

The program in Python is as follows:

fname = input("Enter the translation file name: ")

with open(fname) as file_in:

   lines = []

   for line in file_in:

       lines.append(line.rstrip('\n'))

myDict = {}

for i in range(len(lines)):

x = lines[i].split(":")

myDict[x[0].lower()] = x[1].lower()

print("Enter an English word to receive the Spanish translation.\nPress ENTER to quit.")

word = input("Enter an English word: ")

while(True):

if not word:

 break

if word.lower() in myDict:

 print("The Spanish word is ",myDict[word.lower()])

else:  

 print("I don’t have that word in my list.")

word = input("Enter an English word: ")

Explanation:

This prompts the user for file name

fname = input("Enter the translation file name: ")

This opens the file for read operation

with open(fname) as file_in:

This creates an empty list

   lines = []

This reads through the lines of the file

   for line in file_in:

This appends each line as an element of the list

       lines.append(line.rstrip('\n'))

This creates an empty dictionaty

myDict = {}

This iterates through the list

for i in range(len(lines)):

This splits each list element by :

x = lines[i].split(":")

This populates the dictionary with the list elements

myDict[x[0].lower()] = x[1].lower()

This prints an instruction on how to use the program

print("Enter an English word to receive the Spanish translation.\nPress ENTER to quit.")

This prompts the user for an English word

word = input("Enter an English word: ")

This loop is repeated until the user presses the ENTER key

while(True):

If user presses the ENTER key

if not word:

The loop is exited

 break

If otherwise, this checks if the word exists in the dictionary

if word.lower() in myDict:

If yes, this prints the Spanish translation

 print("The Spanish word is ",myDict[word.lower()])

If otherwise,

else:

Print word does not exist

 print("I don’t have that word in my list.")

Prompt the user for another word

word = input("Enter an English word: ")

5 0
3 years ago
Write a Java program that can calculate and print out the area of a circle. The user enters data of the radius and its measureme
mezya [45]

Answer:

// program in java.

// package

import java.util.*;

// class definition

class Main

{

   // main method of the class

public static void main (String[] args) throws java.lang.Exception

{

   try{

  // Scanner object to read input

Scanner scr=new Scanner(System.in);

 // variables

double rad;

String unit1="in";

String unit2="ft";

String unit3="cm";

String unit4="m";

// ask user to enter radius

System.out.print("Enter the radius: ");

 // read radius

rad=scr.nextDouble();

 // check radius is negative or not

while(rad<0)

{

    System.out.println("Radius can't be negative:");

     // ask again to enter radius

    System.out.print("Enter the Radius again:");

     // read radius again

    rad=scr.nextInt();

}

// ask user to enter the unit of measurement

System.out.print("Enter the unit (\"in\" for inch, \"ft\" for feet, \"cm\" for centimeter, and \"m\" for meter):");

 // read unit

 String unt=scr.next();

 // calculate area

double area=3.14*rad*rad;

 // print area and unit

if(unt.equals(unit1))

    System.out.println(area+" inch.");

else if(unt.equals(unit2))

    System.out.println(area+" feet.");

else if(unt.equals(unit3))

    System.out.println(area+" centimeter.");

else if(unt.equals(unit4))

    System.out.println(area+" meter.");

   }catch(Exception ex){

       return;}

}

}

Explanation:

Read radius of circle from user with Scanner object and assign it to variable "rad".Check the radius is negative or not.If the radius is negative ask user to enter radius again until user enters a positive radius.Then read the unit of measurement.calculate the area of circle and print area with unit.

Output:

Enter the radius: -4

Radius can't be negative:

Enter the Radius again:6

Enter the unit ("in" for inch, "ft" for feet, "cm" for centimeter, and "m" for meter):cm

Area of circle is 113.03999999999999 centimeter.

5 0
3 years ago
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