Answer:
def sum_1k(M):
s = 0
for k in range(1, M+1):
s = s + 1.0/k
return s
def test_sum_1k():
expected_value = 1.0+1.0/2+1.0/3
computed_value = sum_1k(3)
if expected_value == computed_value:
print("Test is successful")
else:
print("Test is NOT successful")
test_sum_1k()
Explanation:
It seems the hidden part is a summation (sigma) notation that goes from 1 to M with 1/k.
- Inside the <em>sum_1k(M)</em>, iterate from 1 to M and calculate-return the sum of the expression.
- Inside the <em>test_sum_1k(),</em> calculate the <em>expected_value,</em> refers to the value that is calculated by hand and <em>computed_value,</em> refers to the value that is the result of the <em>sum_1k(3). </em>Then, compare the values and print the appropriate message
- Call the <em>test_sum_1k()</em> to see the result
Answer:
The answer varies from person to person.
Explanation:
All kinds of people are using Word, so people would recognize if the answer if plagiarized. So, simply answer truthfully; no matter h1ow embarrasing.
Rapid Application Development is the specific term
Answer:
Here!
Hope this helps. Please mark brainliest!
Answer:
for count in range (5,8): numA=numA+count print(numA)
Explanation:
