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kumpel [21]
3 years ago
6

Suppose for the worst case, given input size n: Algorithm 1 performs f(n) = n2 + n/2 steps Algorithm 2 performs f(n) = 12n + 500

steps What is the smallest value of n for which algorithm 2 will be faster than algorithm 1?
Computers and Technology
1 answer:
melomori [17]3 years ago
6 0

Answer:

29

Explanation:

for n=28:

--------------

Algorithm 1 performs f(n) = n2 + n/2 = 28*28 + 28/2 = 798

Algorithm 2 performs f(n) = 12*28 + 500 = 836

for n=29

--------------

Algorithm 1 performs f(n) = n2 + n/2 = 29*29 + 29/2 = 855.5

Algorithm 2 performs f(n) = 12*29 + 500 = 848

so, for n=29, algorithm 2 will be faster than algorithm 1

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siniylev [52]

Answer:

IDF cable

Explanation:

An IDF cable or intermediate distribution frame is a cable rack that interconnects and manages a MDF or main distribution frame and a collection of workstations or computer systems. The MDF is a cable rack that interconnects several IDFs to itself.

4 0
3 years ago
The Polish mathematician Wacław Sierpiński described the pattern in 1915, but it has appeared in Italian art since the 13th cent
soldi70 [24.7K]

Answer:

/ Sierpinski.java

public class Sierpinski {

     // method to find the height of an equilateral triangle with side length =

     // length

     public static double height(double length) {

           // formula= length*sqrt(3)/2

           double h = (length * Math.sqrt(3)) / 2.0;

           return h;

     }

     // method to draw a filled triangle (pointed downwards) with bottom vertex

     // x,y

     public static void filledTriangle(double x, double y, double length) {

           // finding height

           double h = height(length);

           // filling triangle as a polygon

           // passing x, x-length/2, x+length/2 as x coordinates

           // and y, y+h, y+h as y coordinates

           StdDraw.filledPolygon(new double[] { x, x - (length / 2.0),

                       x + (length / 2.0) }, new double[] { y, y + h, y + h });

     }

     // method to draw an n level sierpinski triangle

     public static void sierpinski(int n, double x, double y, double length) {

           // checking if n is above 0 (base condition)

           if (n > 0) {

                 // drawing a filled triangle with x, y as bottom coordinate, length

                 // as side length

                 filledTriangle(x, y, length);

                 // drawing the triangle(s) on the top

                 sierpinski(n - 1, x, y + height(length), length / 2);

                 // drawing the triangle(s) on the left side

                 sierpinski(n - 1, x - (length / 2.0), y, length / 2);

                 // drawing the triangle(s) on the right side

                 sierpinski(n - 1, x + (length / 2.0), y, length / 2);

           }

     }

     public static void main(String[] args) {

           // parsing first command line argument as integer, if you dont provide

           // the value while running the program, this program will cause

           // exception.

           int n = Integer.parseInt(args[0]);

           // length of the outline triangle

           double length = 1;

           // finding height

           double h = height(length);

           // drawing a triangle (pointed upwards) to represent the outline.

           StdDraw.polygon(new double[] { 0, length / 2, length }, new double[] {

                       0, h, 0 });

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           // coordinates and length / 2 as initial side length

           sierpinski(n, length / 2, 0, length / 2);

     }

}

7 0
3 years ago
A blank is the full web Address for particular website<br> (Computer technology)
Yuki888 [10]
What do you mean by that
6 0
3 years ago
¿Cuál es la potencia de una lámpara de incandescencia que se conecta a la red de 220 V, sabiendo que tiene una resistencia de 50
Juliette [100K]

Answer:

  • <u>1,000W</u> (rounded to one significant figure)

Explanation:

I will answer in English.

The question is:

  • <em>What is the power of a filament lamp that connects to the 220 V network, knowing that it has a resistance of 50 ohms?</em>

<em />

<h2>Solution</h2>

<em />

<em>Power</em>, <em>voltage</em>, <em>resistance</em>, and current, are related by either of the following equations:

  • P = V × I
  • P = R × I²
  • P = V² / R

Where:

  • P is power in watts (W)
  • R is resistance in ohms (Ω)
  • V is voltage in volts (V), and
  • I is current in amperes (A)

Since you know the voltage (<em>220V</em>) and the resistance (<em>50Ω</em>), you can use the last equation:

  • P = V² / R
  • P = (220v)² / (50Ω)
  • P = 968 W

Since the magnitude 50Ω has one significant figure, your answer should be rounded to one significant figure. That is <u>1,000W.</u>

7 0
3 years ago
What is the purpose of concatenation?
bearhunter [10]

Explanation:

Concatenation allows you to add multiple strings together to form one long string by using the '+' operator between each string, so the purpose of concatenation is "<em>to combine two or more strings into one big string</em>" (third option).

Hope this helps :)

6 0
3 years ago
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