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dybincka [34]
4 years ago
13

The following data points represent the weight (in

Mathematics
1 answer:
Inessa [10]4 years ago
6 0

Answer:

σ = 3.08

Step-by-step explanation:

Given

6, 5, 13, 8

Required

Standard Deviation

Take note of the following highlighted steps

1. Calculate the Mean

Mean = summation of data ÷ number of data

Summation = 6 + 5 + 13 + 8

Summation = 32

Number of data = 4

Mean = 32/4

Mean = 8

2. Subtract the mean from given data

6:-> 6 - 8 = -2

5:-> 5 - 8 = -3

13:-> 13 - 8 = 5

8:-> 8 - 8 = 0

We have; -2, -3, 5, 0

3. Square these results

-2:-> -2² = 4

-3:-> -3² = 9

5:-> 5² = 25

0:-> 0² = 0

We have: 4, 9, 25, 0

4. Calculate the mean of these results

Mean = summation of data ÷ number of data

Summation = 4 + 9 + 25 + 0

Summation = 38

Number of data = 4

Mean = 38/4

Mean = 9.5

Step 5: Take square root of the above

Standard Deviation, σ = √9.5

σ = 3.08220700148

σ = 3.08 (Approximated)

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Answer: 24$

Explanation:

72 / 6 = 12$

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5 0
3 years ago
The equation y= 1/2 x +4 is graphed below.which equation would intersect this line at (4, 6)?
Anton [14]

Answer:

we have the equation y = (1/2)*x + 4.

now, any equation that passes through the point (4, 6) will intersect this line, so if we have an equation f(x), we must see if:

f(4) = 6.

if f(4) = 6, then f(x) intersects the equation y = (1/2)*x + 4 in the point (4, 6).

If we want to construct f(x), an easy example can be:

f(x) = y = k*x.

such that:

6 = k*4

k = 6/4 = 3/2.

then the function

f(x) = y= (3/2)*x intersects the equation  y = (1/2)*x + 4 in the point (4, 6)

5 0
3 years ago
given y&gt;0 and dy/dx=(3x^2+4x)/yif the point (1,√10) is on the graph relating x and y, then what is y when x=0
jonny [76]
\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{3x^2+4x}y\iff y\,\mathrm dy=(3x^2+4x)\,\mathrm dx
\implies\displaystyle\int y\,\mathrm dy=\int(3x^2+4x)\,\mathrm dx
\implies \dfrac12y^2=x^3+2x^2+C

When x=1 you have y=\sqrt{10}, so

\dfrac12(\sqrt{10})^2=1^3+2(1)^2+C\implies 5=1+2+C\implies C=2

and so the particular solution to the ODE is

\dfrac12y^2=x^3+2x^2+2

Then when x=0, you get

\dfrac12y^2=0^3+2(0)^2+2=2
\implies y^2=4
\implies y=2

where we omitted the negative root because it's given that y>0.
4 0
3 years ago
What is the average rate of change of the line whose equation is y-5=-(x-3)?
lana66690 [7]
The answer of the equation is 0
8 0
4 years ago
HELP PLS!
Zigmanuir [339]

Answer:

x = 2  is the correct answer :)

5 0
3 years ago
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