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2 years ago

Question 4

Mathematics

2 answers:

3241004551 [841]2 years ago

8 0

Answer:

No, there is no change in the relationship. The slopes of AC and DE continue to be equal, and the length of DE remains half of the length of AC.

Step-by-step explanation:

The answer is from Plato. I hope this helps :)

serg [7]2 years ago

7 0

Answer:

No, the connection has not changed. The slopes of AC and DE are still equal, and the length of DE is still half that of AC.

Step-by-step explanation:

From Plato but in my own words! :)

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Use absolute value to write an expression describing the size of each amount. An elevation of 250 feet.

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Use the absolute value.

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An elevation of 250 feet = +250

then, using absolute value:

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2 years ago

What is the equation of the circle whose diameter has endpoints (8,-2) and (-2,6)?

klemol [59]

Answer:

$(x-3)^{2} +(y-2)^{2}=41$

Step-by-step explanation:

step 1

Find the diameter of the circle

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$A(8,-2)\\E(-2,6)$

substitute the values

$d=\sqrt{(6+2)^{2}+(-2-8)^{2}}$

$d=\sqrt{(8)^{2}+(-10)^{2}}$

$d=\sqrt{164}\ units$

$d=2\sqrt{41}\ units$

step 2

Find the center of the circle

The center is the midpoint of the diameter

The center is equal to

$C=(\frac{8-2}{2},\frac{-2+6}{2})$

$C=(3,2)$

step 3

Find the equation of the circle

The equation of the circle in center radius form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

we have

(h,k)=(3,2)

$r=2\sqrt{41}/2=\sqrt{41}\ units$ ---> the radius is half the diameter

substitute

$(x-3)^{2} +(y-2)^{2}=(\sqrt{41})^{2}$

$(x-3)^{2} +(y-2)^{2}=41$

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3 years ago