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Vera_Pavlovna [14]
3 years ago
13

Need help with this problem

Mathematics
1 answer:
Zanzabum3 years ago
7 0

Answer:

C. Priya needs to charge at least $21 per bracelet.

Step-by-step explanation:

117b - 505 \ge 1952

Add 505 to both sides.

117b \ge 2457

Divide both sides by 117.

b \ge 21

Answer: C. Priya needs to charge at least $21 per bracelet.

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What decimal is equivalent to 27/32
PilotLPTM [1.2K]

Answer:

0.8438

0.8438 is a decimal and 84.38/100 or 84.38% is the percentage for 27/32.

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
A simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week
Levart [38]

Answer:

99% confidence interval for the population proportion of employed individuals is [0.104 , 0.224].

Step-by-step explanation:

We are given that a simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week.

Of the 250 employed individuals​ surveyed, 41 responded that they did work at home at least once per week.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

                              P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of individuals who work at home at least once per week = \frac{41}{250} = 0.164

           n = sample of individuals surveyed = 250

<em>Here for constructing 99% confidence interval we have used One-sample z proportion statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99  {As the critical value of z at 0.5%

                                             level of significance are -2.5758 & 2.5758}  

P(-2.5758 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 2.5758) = 0.99

P( -2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

P( \hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

<em>99% confidence interval for p</em> = [\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

= [ 0.164-2.5758 \times {\sqrt{\frac{0.164(1-0.164)}{250} } } , 0.164+2.5758 \times {\sqrt{\frac{0.164(1-0.164)}{250} } } ]

 = [0.104 , 0.224]

Therefore, 99% confidence interval for the population proportion of employed individuals who work at home at least once per week is [0.104 , 0.224].

7 0
2 years ago
A rectangular window measures 54 inches by 24 inches. There is an a = 14-inch wiper blade attached by a b = 5-inch arm at the ce
nika2105 [10]
It the wiper blade (and arm) made a full rotation, 2 circles would be formed.

One small circle with radius b, and a larger circle with radius a+b.


The areas of these 2 circles are respectively:

\pi b^2=\pi\cdot 5^2=25 \pi (in^2)    and

\pi (a+b)^2=\pi (14+5)^2=361\pi (in^2)


120° is 1/3 of a complete angle 360° which form a circle, so the areas formed by the arm of length b, and the arm + the wiper blade (a+b) are:

\frac{25 \pi}{3} and \frac{361\pi}{3} in squared respectively.

the actual wiped area is \frac{361\pi}{3}-\frac{25 \pi}{3}= \frac{336\pi}{3}=112\pi \approx351.7 (in squared)


Area of the window is 54*24= 1296 (in squared)

thus, the ratio of the wiped area to the whole area of the window is 351.7/1296=0.271

Converted to percentages, this is 27.1%


Answer: 27.1%

3 0
3 years ago
Wesley runs 10 kilometers every day. He runs 6 days per week for 50 minutes per day.
statuscvo [17]

Answer:

don't know maybe 60

Step-by-step explanation:

Idk

8 0
3 years ago
Create interview questions.<br> Conduct three interviews.<br> Answer them. Brainliest!
Igoryamba

Answer:

1. Where are you from

2.why did you want to get this job/position

3.How are your language skills

Step-by-step explanation:

8 0
3 years ago
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