Answer:
we need to prove : for every integer n>1, the number 
is a multiple of 5.
1) check divisibility for n=1, 
(divisible)
2) Assume that 
is divisible by 5, 
3) Induction,
Now, 
Take out the common factor,
(divisible by 5)
add both the sides by f(k)
We have proved that difference between 
and is divisible by 5.
so, our assumption in step 2 is correct.
Since is divisible by 5, then must be divisible by 5 since we are taking the sum of 2 terms that are divisible by 5.
Therefore, for every integer n>1, the number is a multiple of 5.
<h2>Part a)</h2>
You can name planes by one letter or using three points belonging to it that are <u>not</u> on the same line.
Another name for plane X could be:
- Plane ABF, Plane BCF or Plane ACF. You may also get different names by reordering the three letters.
<h2>Part b)</h2>
Coplanar means 'on the same plane'.
The points on the same plane as point A are:
<h2>Part c)</h2>
Collinear means 'on the same line'.
Other points on the same line as point C are:
<h2>Part d)</h2>
The line that intersects ED is:
- AC, it can be also named AB or BC.
Answer:
The answer is 1 and 1/12 you can’t simplify the problem but this is the answer
Step-by-step explanation:
<h2>Domain: {0, 2}</h2><h2>Range: {0, 1, 1}</h2><h2 /><h3>When dealing with the domain, remember that no numbers can repeat in the domain so if there is more than one of the same number, we only list it one.</h3><h3 /><h3>When dealing with the range, it's ok if numbers repeat because it's the y-value not the x-value.</h3><h3 /><h3 />
