Which of the following expressions represents the value, in dollars, of a certain number of dimes, d, and pennies, p?

"The price for an adult movie ticket is 1 1/3 more than a than the price for a child movie ticket" how would I write that?

faltersainse [42]

Answer:

child=x adult=1.33333333333333333333333333333333333333333333x

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The product of three consecutive integers is 3360. What is the sum of the three integers?

Tom [10]

Step-by-step explanation:

let the integer be x .

three consecutive integers : x, x+1, x+2.

according to the problem,.

Let the first of the 3 consecutive numbers be X.

Therefore the second number is (X + 1)

The third number is therefore (X + 2)

The product of the 3 consecutive numbers is:

( X )( X + 1 )( X + 2 ) = 3360 Equation( 1 )

Expanding Equation ( 1 ) gives

X³ + 3X² + 2X - 3360 = 0 Equation (2)

Solve Equation (2 ) which gives the following values for X

X1 = 14

X2 = - 8.5 + i (12.951834)

X3 = - 8.5 - i (12.951834).

the numbers are 14,15,16.

sum is 14+15+16 = 45.

hope this helps you.

5 0

3 years ago

The tires on your bicycle have a radius of 8 inches. How many rotations does each tire make when you travel 700 feet? Round your

Inessa [10]

"One rotation" would be the circumference of the wheel, which is

C = 2*pi*r, or (here) C = 2*pi*(8 inches) = 16*pi inches.

1 ft
Convert this to feet: 16*pi inches times ---------------
12 inches

Here "inches" cancels out and you are left with (4/3)pi ft.

So, one rotation of the wheel moves you and your bike forward (4/3)pi ft.

Divide this into 700 feet:

700 ft 2100
------------- = --------- rotations = 525 rotations (answer)
(4/3) pi ft 4

7 0

4 years ago

Suppose the selling price of homes is skewed right with a mean of 350,000 and a standard deviation of 160000 If we record the se

lys-0071 [83]

Answer:

The distribution will be approximately normal, with mean 350,000 and standard deviation 25,298.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .