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brilliants [131]
4 years ago
15

Please, please help. Answer the question, then explain how you got your answer. a= -3

Mathematics
1 answer:
Mice21 [21]4 years ago
3 0
3.5*(-3)///////3.5*(-3)//////all of this parts same
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In a continuous series, mean(x) = 80, assumed mean(A) = 60 and<br>EF=40 then find the value of EFd.​
Aneli [31]

Using the given information, the value of Σfd is 800

<h3>Calculating mean using Assumed mean </h3>

From the question, we are to determine the value of Σfd

The formula for mean, using the assumed mean method is given by

\bar x = A + \frac{\sum fd}{\sum f}

Where \bar x is the mean

A is the assumed mean

From the given information,

\bar x = 80

A = 60

\sum f = 40

Putting the parameters into the equation, we get

80 = 60 + \frac{\sum fd}{40}

80-60 = \frac{\sum fd}{40}

20 = \frac{\sum fd}{40}

\sum fd = 20 \times 40

\sum fd = 800

Hence, the value of Σfd is 800

Learn more on Mean here: brainly.com/question/20118982

#SPJ1

8 0
2 years ago
Louise is walking 12 miles to raise funds for a local cause. If she has completed 34 of the distance, how many miles has she wal
Elden [556K]
About 4 miles hope this helps
6 0
3 years ago
−(−49) = −49 true or false?
vova2212 [387]

I hope this helps you

false

cause two negative numbers multiple must be positive

(-1).(-49)

+49

5 0
3 years ago
Mrs. Brown hosts an yearly art contest keeps a record of the number of entries each year.
olganol [36]
1. Slope = rate of change
Shown on the graph, for 2016 there are 36 entries. For 2017, there are 40
Since it’s only one year
You can subtract 36 from 40
40 - 36 = 4
Solution: the slope is 4

2. Months increase the most, the lines which are steeper and going upward (since it’s increasing)
Solution: from 2015 to 2016
4 0
3 years ago
There are eight students in a class. Only one of them has passed Exam P/1 and only one of them has passed Exam FM/2. No student
Svetach [21]

Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

Step-by-step explanation:

Total number of students = 8

Number of student who has passed Exam P/1 = 1

Number of student who has passed Exam FM/2 = 1

No student has passed more than one exam.

According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.

So, Probability will be

\frac{^6C_3\times ^2C_1}{^8C_4}\\\\=\frac{20\times 2}{70}\\\\=\frac{4}{7}\\\\=0.57

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

4 0
3 years ago
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