Answer:
0.81 (rounded to the nearest hundredth) & 81%
Step-by-step explanation:
150/185 = 30/37 ≈ 0.81 (rounded to the nearest hundredth)
0.81 is 81%
Answer:
<u>Hence final answer is B: Step 2.</u>
Step-by-step explanation:
Step 1: Find the total points needed to score in six games: 96x6=576
Justification:
Product of 96 and 6 is 576 which is same number found by Brenda. So step 1 is correct.
Step 2: Find the total points scored: 92+110+85+78=365
Justification:
Sum of total points scored by Brenda is 92+110+85+78= 461.
But she got different value 365.
Hence step 2 is wrong.
<u>Hence final answer is B: Step 2.</u>
Answer:
Adult ticket is $60
Child ticket is $32
Step-by-step explanation:
Let x = price of adult ticket
y = price of child ticket
(1) 175x + 103y = 13796 (2) 2x + 2y = 184
x + y = 92
y = 92 - x
175x + 103(92 - x) = 13796
175x + 9476 - 103x = 13796
72x = 4320
x = 60 y = 92 - 60
y = 32
(a) From the histogram, you can see that there are 2 students with scores between 50 and 60; 3 between 60 and 70; 7 between 70 and 80; 9 between 80 and 90; and 1 between 90 and 100. So there are a total of 2 + 3 + 7 + 9 + 1 = 22 students.
(b) This is entirely up to whoever constructed the histogram to begin with... It's ambiguous as to which of the groups contains students with a score of exactly 60 - are they placed in the 50-60 group, or in the 60-70 group?
On the other hand, if a student gets a score of 100, then they would certainly be put in the 90-100 group. So for the sake of consistency, you should probably assume that the groups are assigned as follows:
50 ≤ score ≤ 60 ==> 50-60
60 < score ≤ 70 ==> 60-70
70 < score ≤ 80 ==> 70-80
80 < score ≤ 90 ==> 80-90
90 < score ≤ 100 ==> 90-100
Then a student who scored a 60 should be added to the 50-60 category.
