What is the value of | 5

Please help!! I don’t get it

Marrrta [24]

Answer:

Each hotdog costs $1.65

Each juice drink costs $1.05

Step-by-step explanation:

Let's begin by letting $x$ represent the number of hot dogs and $y$ the number of juice drinks.

The Baxter family bought 6 hot dogs and 4 juices for $14.10.

$6x + 4y = 14.10$

The Farley family bought 3 hot dogs and 4 juices for $9.15.

$3x + 4y = 9.15$

Now, we subtract these equations.

$6x + 4y = 14.10\\- (3x + 4y = 9.15)$

Since $y$ has reversed coefficients, it gets eliminated. Now solve for x.

$6x+4y-3x-4y=14.1-9.15\\3x = 4.95\\\frac{3x}{3} = \frac{4.95}{3}$

$\frac{4.95}{3} = 1.65$

$x = 1.65$

NOW, we find y by substituting x with 1.65 (in either equation).

We'll use the first equation.

$6x + 4y = 14.10$

$6(1.65) + 4y = 14.10$

$9.9 + 4y = 14.10\\4y = 14.1 - 9.9\\4y = 4.2$

$\frac{4y}{4} = \frac{4.2}{4} \\y = 1.05$

$x$ = 1.65

$y$ = 1.05

$x$ represents hotdogs and $y$ represents juice drinks.

Therefore, each hotdog costs $1.65 and each juice drink costs $1.05.

I hope this helps! :)

6 0

2 years ago

Which choice is right

zysi [14]

A is the right answer

8 0

3 years ago

What function corresponds to the ordered pairs shown in the table?

Anettt [7]

well, we know it's a line, and to get the equation of any line all we need is two points, let's pick two from the table hmmmm say let's use (-3 , -7) and (3 , 11)

$(\stackrel{x_1}{-3}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{11}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{11}-\stackrel{y1}{(-7)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{(-3)}}}\implies \cfrac{11+7}{3+3}\implies \cfrac{18}{6}\implies 3$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{3}(x-\stackrel{x_1}{(-3)}) \\\\\\ y+7=3(x+3)\implies y+7=3x+9\implies y = 3x+2$

6 0

2 years ago

What is the minimum number of base-ten pieces needed to replace each set?

andreev551 [17]

Answer:

The answer is .B

Step-by-step explanation:

Hope this can help you !

3 0

2 years ago

Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive

LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c) The probability that exactly 1 of the next three vehicles passes is 0.189.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let X = number of vehicles that pass the inspection.

The probability of the random variable X is P (X) = 0.70.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

$=(0.70)^{3}\\=0.343$

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

$=1-0.343\\=0.657$

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

= P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

+ P (Only 3rd vehicle passes)

$=(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189$

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

+ P (0 vehicles passes)

$=0.189+(0.30\times0.30\times0.30)\\=0.216$

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let X = all 3 vehicle passes and Y = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

$P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525$

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0

2 years ago

What is the value of | 5 | + |-2 |?