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3 years ago

15

WILL GIVE BRAINLIEST solve for x A. 70/6 B. 60/16 C. 6 D. 11

1 answer:

miss Akunina [59]3 years ago

3 0

So a line is 180°
Since it gave you options, the easiest way would be to plug it in (plug and chug)
the answer is 11
first what I did was plug 12 into 5x+10 and then found the answer and then added 58°
the answer of that subtracted from 180
with that I then plugged in 11 for x for 11x+2 = 123
180 - 123 = 57 which is the same answer for the missing angle within the triangle

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The use of mathematical methods to study the spread of contagious diseases goes back at least to some work by Daniel Bernoulli i

harina [27]

Answer:

a

$y(t) = y_o e^{\beta t}$

b

$x(t) = x_o e^{\frac{-\alpha y_o }{\beta }[e^{-\beta t} - 1] }$

c

$\lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }$

Step-by-step explanation:

From the question we are told that

$\frac{dy}{y} = -\beta dt$

Now integrating both sides

$ln y = \beta t + c$

Now taking the exponent of both sides

$y(t) = e^{\beta t + c}$

=> $y(t) = e^{\beta t} e^c$

Let $e^c = C$

So

$y(t) = C e^{\beta t}$

Now from the question we are told that

$y(0) = y_o$

Hence

$y(0) = y_o = Ce^{\beta * 0}$

=> $y_o = C$

So

$y(t) = y_o e^{\beta t}$

From the question we are told that

$\frac{dx}{dt} = -\alpha xy$

substituting for y

$\frac{dx}{dt} = - \alpha x(y_o e^{-\beta t })$

=> $\frac{dx}{x} = -\alpha y_oe^{-\beta t} dt$

Now integrating both sides

$lnx = \alpha \frac{y_o}{\beta } e^{-\beta t} + c$

Now taking the exponent of both sides

$x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} + c}$

=> $x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} } e^c$

Let $e^c = A$

=> $x(t) =K e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }$

Now from the question we are told that

$x(0) = x_o$

So

$x(0)=x_o =K e^{\alpha \frac{y_o}{\beta } e^{-\beta * 0} }$

=> $x_o = K e^{\frac {\alpha y_o }{\beta } }$

divide both side by $(K * x_o)$

=> $K = x_o e^{\frac {\alpha y_o }{\beta } }$

So

$x(t) =x_o e^{\frac {-\alpha y_o }{\beta } } * e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }$

=> $x(t)= x_o e^{\frac{-\alpha * y_o }{\beta} + \frac{\alpha y_o}{\beta } e^{-\beta t} }$

=> $x(t) = x_o e^{\frac{\alpha y_o }{\beta }[e^{-\beta t} - 1] }$

Generally as t tends to infinity , $e^{- \beta t}$ tends to zero

so

$\lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }$

5 0

3 years ago

What is 7,5444+789=?

lisov135 [29]

Answer:

76233

Step-by-step explanation:

Add the numbers together:

75444 + 789 = 76233

3 0

3 years ago

Read 2 more answers

Find exact value for cos(pi/16)

stellarik [79]

The exact value for cos(pi/16) would be :

cos (pi/16) = +/- √1+cosa/2

cos (pi/4) = sqrt2/2

Hope this helps

6 0

3 years ago

Which equation has only 1 solution? A. c+2=c+2 B. c= -c+2 C. c+2=c-2 D. c-c=2 Please explain.

zhannawk [14.2K]

Answer:

B. c= -c+2

Step-by-step explanation:

A. ...................

c+2=c+2
c-c= 2-2
0=0

It has infinitely many solutions as the equation is correct for any value of c.

B. ...................

c= -c+2
c+c= 2
2c = 2
c = 2/2
c= 1

It has one solution only

C. ...................

c+2=c-2
c-c= -2 - 2
0 = -4

It has no solution as this equation is incorrect

D. ...................

c-c=2
0 = 2

It has no solution as this equation is incorrect

6 0

3 years ago

Is 5.75 a terminating decimal or repeating decimal?

yawa3891 [41]

Terminated. Any decimal that repeats goes on forever. Such as pie: 3.1415...

3 0

3 years ago