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3 years ago

How many minutes of calling time do the plans cost the same amount ?

Mathematics

1 answer:

Mama L [17]3 years ago

7 0

D 200 minutes

.15*200 = 30+45= Plan A= $75
.25*200= 50+25= Plan B= $75

Answer is D

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Find the equation of the line between (-7,4) and (5,9) in slope intercept form

matrenka [14]

Step-by-step explanation:

(9-4)/(5+7)= 5/12

y - 4 = 5/12(x + 7)

y - 48/12 = (5/12)x + 35/12

y = (5/12)x + 83/12

4 0

3 years ago

natulia [17]

Answer:

diagonal = = 12.8 inches (to the nearest tenth of an inch)

Step-by-step explanation:

As shown in the diagram attached to this solution:

Let the Length of the rectangular board = a

Let the width = b

Let the diagonal = d

where:

a = 10 inches

b = 8 inches

d = ?

Triangle ABC in the diagram is a right-angled triangle, therefore, applying Pythagoras theorem:

(hypotenuse)² = (Adjacent)² + (Opposite)²

d² = 10² + 8²

d² = 100 + 64

d² = 164

∴ d = √(164)

d = 12.806 inches

d = 12.8 inches (to the nearest tenth of an inch)

N:B Rounding off to the nearest tenth of an inch is the same as rounding off to 1 decimal place.

3 0

3 years ago

The scatter plot shows the number of hats and scarves each knitter sold at a knitting show.

SOVA2 [1]

I believe your answer should be 5!

4 0

3 years ago

Read 2 more answers

A person borrows $50000 loan from bank at a rate of 10% for 5 years compounded yearly.

Hatshy [7]

<h3>Given:</h3>

P= $50,000
R= 10%
T= 5 years

P= Principal amount
R= Rate of interest
T= Time period

<h3>Solution:</h3>

$\large\boxed{Formula: A= P(1+ \frac{R}{100}{)}^{T}}$

Let's substitute according to the formula.

$A= 50000(1+ \frac{10}{100}{)}^{5}$

A= $80525.5

Now, we can find the interest paid

$\large\boxed{I= A-P}$

We'll have to deduct the total amount from the principal amount.

Let's substitute according to the formula.

$I= 80525.5-50000$

I= $30525.5

Hence, the total amount paid after 5 years is $80525.5 and $30525.5 was paid as interest.

7 0

2 years ago

I do not even know where to begin. Please help.

xenn [34]

F(x) = 2x + 1 when x <= -5
Now -10 is less than -5 so we plug x = -10 into 2x +1:-

f(-10) = 2(-10) + 1 = -19 answer

Now f(x) = x^2 when -5< x < 5
x =2 is within this range so f(2) = 2^2 = 4 answer

You can calculate the other 3 values by a similar method

5 0

3 years ago