Let the number of bike be x and the number of skates be y, then
21x + 20y ≥ 362 . . . (1)
2y = x . . . (2)
Putting (2) into (1), then
21(2y) + 20y ≥ 362
42y + 20y ≥ 362
62y ≥ 362
y ≥ 5.84
The least number of pairs of skates they need to rent each day to make their minimum is 6.
Answer:
2
Step-by-step explanation:
I got it right on my work I did the other day
Step-by-step explanation:
Take the number as x
12x-40=7x+25
collect like terms
12x-7x=25+40
5x=65(divide both sides by 5)
x=13
Therefore number is 13
It’s a big problem it’s deserve 20 points you can’t play people make it fair