Pythagorean theorem states that:
c^2=a^2+b^2
where:
c=hypotenuse
a and b are the legs
this implies that, a and b are shorter than c; thus to find the Pythagorean theorem we look for values that satisfy the above equation, where c is the longest side.
17^2=15^2+9^2
thus (17,15,9) are Pythagorean triple.
13^2=5^2+12^2
Thus (5,12,13) are Pythagorean triple
12^2≠6^2+8^2
Thus they are not Pythagorean triple
6^2=5^2+3^2
Thus (3,5,6) are not Pythagorean theorem.
I will give two solutions, one where everything is cubed and one where just the 3 is cubed, because I don't know what you meant.
Just the 3 is cubed solution(Which I think is correct because it has a nicer answer):
Answer:

Step-by-step explanation:
We have that
.
We can subtract
from both sides of the equation to get
.
We can then divide by
to get
.
So,
and we're done!
Everything is cubed solution:
Answer:
![\sqrt[3]{5}-3/2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%7D-3%2F2)
Step-by-step explanation:
We have that
.
We can take the cube root of both sides to get
.
Note that
, so
.
So, we want to solve
.
We can subtract
from both sides to get
.
We can then divide both sides by
to get
.
So,
and we're done!
I have to say its
<span>−64 and 64</span>