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sdas [7]
3 years ago
15

-13>w+12 please help

Mathematics
1 answer:
Taya2010 [7]3 years ago
4 0

Answer:

Step-by-step explanation:

-13>w+12

-12-13>w

-25>w

w< -25

w={......-27,-26}

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I WILL GIVE BRAINLIEST
adelina 88 [10]

Answer: 2x - 1 (+x) =19

4 0
3 years ago
WHich of the following sets of integers is a Pythagorean triple?
aalyn [17]
Pythagorean theorem states that:
c^2=a^2+b^2
where:
c=hypotenuse
a and b are the legs
this implies that, a and b are shorter than c; thus to find the Pythagorean theorem we look for values that satisfy the above equation, where c is the longest side.
17^2=15^2+9^2
thus (17,15,9) are Pythagorean triple.

13^2=5^2+12^2
Thus (5,12,13) are Pythagorean triple

12^2≠6^2+8^2
Thus they are not Pythagorean triple

6^2=5^2+3^2
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7 0
4 years ago
Read 2 more answers
Is the answer 1.1 reasonable for 4.4-0.33
Vikentia [17]
No, the answer is 4.07
6 0
3 years ago
What is the value of x, if twice x plus 3 cubed equals 40?
tatuchka [14]

I will give two solutions, one where everything is cubed and one where just the 3 is cubed, because I don't know what you meant.

Just the 3 is cubed solution(Which I think is correct because it has a nicer answer):

Answer:

13/2

Step-by-step explanation:

We have that 2x+3^3=40.

We can subtract 3^3=27 from both sides of the equation to get 2x=13.

We can then divide by 2 to get x=13/2.

So, \boxed{x=13/2} and we're done!

Everything is cubed solution:

Answer:

\sqrt[3]{5}-3/2

Step-by-step explanation:

We have that (2x+3)^3=40.

We can take the cube root of both sides to get 2x+3=\sqrt[3]{40}.

Note that 40=2^3*5, so \sqrt[3]{40}=\sqrt[3]{2^3*5}=2\sqrt[3]{5}.

So, we want to solve 2x+3=2\sqrt[3]{5}.

We can subtract 3 from both sides to get 2x=2\sqrt[3]{5}-3.

We can then divide both sides by 2 to get x=\sqrt[3]{5}-3/2.

So, \boxed{x=\sqrt[3]{5}-3/2} and we're done!

6 0
3 years ago
Solve for x.
Flauer [41]
I have to say its
<span>−64 ​ and 64</span>
4 0
3 years ago
Read 2 more answers
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