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Over [174]
3 years ago
15

Which of the following is the solution set of the equation

Mathematics
1 answer:
svet-max [94.6K]3 years ago
6 0
<span>Which of the following is the solution set of the equation
10(x^2+1/x^20)-63(x-1/x)=52=0
I think you type wrongly the equation:
It is : </span><span>10(x^2+1/x^2)-63(x-1/x)+52=0
We know: x</span>²+1/x²=(x-1/x)²+2, pose x-1/x=t and we have x²+1/x²=t²+2
So 10(t²+2)-63t+52=0
or 10t²-63t+72=0
we have t=(63+33):20= 24/5
and t=(63-33):20=3/2

+ If t=3/2 we have x-1/x=3/2 or 2x²-3x-2=0 and we have x=2, x=-1/2
+ Of t=24/5 we have x-1/x=24/5 or 5x²-24x-5=0 or x=5 and x=-1/5

And the answer: <span>c) (5,2,-1/5,-1/2)</span>
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