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Ilia_Sergeevich [38]
3 years ago
10

Im losing brain cells please answer

Mathematics
2 answers:
Irina18 [472]3 years ago
6 0

Answer:

A...i think

Step-by-step explanation:

icang [17]3 years ago
6 0
The answer is D, since her sister is four years older than her.
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To get from one town to another, Jack must travel 7 miles east and 24 miles south. What is the direct distance between the two t
Step2247 [10]
The 7 miles and 24 miles make up two "legs" of a right triangle.
The third side (or hypotenuse) is the distance between the towns.
distance^2 = 7^2 + 24^2
distance^2 = 49 + 576
distance^2 = 625
distance = square root of 625 or 25
3 0
4 years ago
PLEASE HELP ILL GIVE BRAINLIEST
Art [367]

Answer: 10

Step-by-step explanation:

count the dots from number 2 and below

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3 years ago
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Who does gyro never never ever bet on even numbers math worksheet!!
uranmaximum [27]
I really do not know the answer to this question
6 0
3 years ago
sarah had 28 stickers and put x number of stickers on her binded. haylee had 40 stickers and put three times as many stickers on
Mariana [72]

Answer:

Number of stickers Sarah had = 28

Number of stickers she put on her binder = x.

Number of stickers left with her = 28 - x

Number of stickers Haylee had = 40

Number of stickers she put on her locker = 3x

Number of stickers left with her = 40 - 3x

Both Sarah and Haylee had the same number of stickers left.

28 - x = 40 - 3x

=> 3x - x = 40 - 28

=> 2x = 12

=> x =  = 6

Step-by-step explanation:

7 0
3 years ago
Which of the following is not a property of a chi-square distribution?
laiz [17]

Answer:

c) Is not a property (hence (d) is not either)

Step-by-step explanation:

Remember that the chi square distribution with k degrees of freedom has this formula

\chi_k^2 = \matchal{N}_1^2 +  \matchal{N}_2^2 + ... + \, \matchal{N}_{k-1}^2 +  \matchal{N}_k^2

Where N₁ , N₂m .... N_k are independent random variables with standard normal distribution. Since it is a sum of squares, then the chi square distribution cant take negative values, thus (c) is not true as property. Therefore, (d) cant be true either.

Since the chi square is a sum of squares of a symmetrical random variable, it is skewed to the right (values with big absolute value, either positive or negative, will represent a big weight for the graph that is not compensated with values near 0). This shows that (a) is true

The more degrees of freedom the chi square has, the less skewed to the right it is, up to the point of being almost symmetrical for high values of k. In fact, the Central Limit Theorem states that a chi sqare with n degrees of freedom, with n big, will have a distribution approximate to a Normal distribution, therefore, it is not very skewed for high values of n. As a conclusion, the shape of the distribution changes when the degrees of freedom increase, because the distribution is more symmetrical the higher the degrees of freedom are. Thus, (b) is true.

6 0
3 years ago
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